C++ Type_info Library - operator!= Function

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Description

It returns whether the types identified by two type_info objects are not the same.

Declaration

Following is the declaration for std::type_info::operator!=

C++98

	
bool operator!= (const type_info& rhs) const;

C++11

bool operator!= (const type_info& rhs) const noexcept;

Parameters

rhs − It identify the object type.

Return Value

It returns whether the types identified by two type_info objects are not the same.

Exceptions

No-throw guarantee − this member function never throws exceptions.

Data races

The locale object is modified.

Example

In below example for std::type_info::operator!=.

#include <iostream>
#include <typeinfo>
#include <string>
#include <utility>
 
class person {
   public:

      person(std::string&& n) : _name(n) {}
      virtual const std::string& name() const{ return _name; }

   private:

      std::string _name;
};

class employee : public person {
   public:

      employee(std::string&& n, std::string&& p) :
         person(std::move(n)), _profession(std::move(p)) {}

      const std::string& profession() const { return _profession; }

   private:

      std::string _profession;
};

void somefunc(const person& p) {
   if(typeid(employee) == typeid(p)) {
      std::cout << p.name() << " is an employee ";
      auto& emp = dynamic_cast<const employee&&gt;(p);
      std::cout << "who works in " << emp.profession() << '\n';
   }
}

int main() {
   employee paul("sairamkrishna","tutorialspoint");
   somefunc(paul);
}

The output should be like this −

sairamkrishna is an employee who works in tutorialspoint