C++ List Library - get_allocator() Function


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Description

The C++ function std::list::get_allocator() returns an allocator associated with list.

Declaration

Following is the declaration for std::list::get_allocator() function form std::list header.

C++98

allocator_type get_allocator() const;

C++11

allocator_type get_allocator() const noexcept;

Parameters

None

Return value

Returns an allocator associated with list.

Exceptions

This member function never throws exception.

Time complexity

Constant i.e. O(1)

Example

The following example shows the usage of std::list::get_allocator() function.

#include <iostream>
#include <list>

using namespace std;

int main(void) {
   list<int> l = {1, 2, 3, 4, 5};
   int *p = NULL;

   p = l.get_allocator().allocate(5);

   for (int i = 0; i < 5; ++i)
      p[i] = i + 1;

   cout << "List contains following elements" << endl;

   for (int i = 0; i < 5; ++i)
      cout << p[i] << endl;

   return 0;
}

Let us compile and run the above program, this will produce the following result −

List contains following elements
1
2
3
4
5
list.htm
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