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C++ code to find out if a name is male or female
Suppose, we are given n strings in an array 'input'. The strings are names, we have to find out if they are male or female names. If a name ends with 'a', 'e', 'i', or 'y'; it can be said that it is a female name. we print 'male' or 'female' for each input in the string.
So, if the input is like n = 5, input = {"Lily", "Rajib", "Thomas", "Riley", "Chloe"}, then the output will be Female, Male, Male, Female, Female.
Steps
To solve this, we will follow these steps −
for initialize i := 0, when i < n, update (increase i by 1), do: s := input[i] l := size of s if s[l - 1] is same as 'a' or s[l - 1] is same as 'e' or s[l - 1] is same as 'i' or s[l - 1] is same as 'y', then: print("Female") Otherwise, print("Male")
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h> using namespace std; #define N 100 void solve(int n, string input[]) { for(int i = 0; i < n; i++) { string s = input[i]; int l = s.size(); if (s[l - 1] == 'a' || s[l - 1] == 'e' || s[l - 1] == 'i' || s[l - 1] == 'y') cout<< "Female" << endl; else cout << "Male" << endl; } } int main() { int n = 5; string input[] = {"Lily", "Rajib", "Thomas", "Riley", "Chloe"}; solve(n, input); return 0; }
Input
5, {"Lily", "Rajib", "Thomas", "Riley", "Chloe"}
Output
Female Male Male Female Female
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