C++ code to find out which number can be greater

Suppose, we are given two k-digit numbers m and n. The digits of the numbers are randomly shuffled and then compared. We have to find out which number has a higher probability to be greater.

So, if the input is like n = 231, m = 337, k = 3, then the output will be ‘Second’, or the second number has a higher probability to be greater.

Steps

To solve this, we will follow these steps −

s1 := convert n to string
s2 := convert m to string
f := 0, s = 0
for initialize i := 0, when i < k, update (increase i by 1), do:
   if s1[i] > s2[i], then:
      (increase f by 1)
   otherwise when s1[i] < s2[i], then:
      (increase s by 1)
if f > s, then:
   print("First")
otherwise when s > f, then:
   print("Second")
Otherwise
   print("Equal")

Example

Let us see the following implementation to get better understanding −

#include <bits/stdc++.h>
using namespace std;
#define N 100
void solve(int n, int m, int k) {
   string s1 = to_string(n);
   string s2 = to_string(m);
   int f = 0, s = 0;
   for(int i = 0; i < k; i++){
      if(s1[i] > s2[i])
         f++;
      else if(s1[i] < s2[i])
         s++;
   }
   if(f > s)
      cout<<"First"<<endl;
   else if(s > f)
      cout<<"Second"<<endl;
   else
      cout<<"Equal"<<endl;
}
int main() {
   int n = 231, m = 337, k = 3;
   solve(n, m, k);
   return 0;
}

Input

231, 337, 3

Output

Second

Arnab Chakraborty

Updated on 29-Mar-2022 08:50:15

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