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C++ code to find out which number can be greater
Suppose, we are given two k-digit numbers m and n. The digits of the numbers are randomly shuffled and then compared. We have to find out which number has a higher probability to be greater.
So, if the input is like n = 231, m = 337, k = 3, then the output will be ‘Second’, or the second number has a higher probability to be greater.
Steps
To solve this, we will follow these steps −
s1 := convert n to string
s2 := convert m to string
f := 0, s = 0
for initialize i := 0, when i < k, update (increase i by 1), do:
if s1[i] > s2[i], then:
(increase f by 1)
otherwise when s1[i] < s2[i], then:
(increase s by 1)
if f > s, then:
print("First")
otherwise when s > f, then:
print("Second")
Otherwise
print("Equal")Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
#define N 100
void solve(int n, int m, int k) {
string s1 = to_string(n);
string s2 = to_string(m);
int f = 0, s = 0;
for(int i = 0; i < k; i++){
if(s1[i] > s2[i])
f++;
else if(s1[i] < s2[i])
s++;
}
if(f > s)
cout<<"First"<<endl;
else if(s > f)
cout<<"Second"<<endl;
else
cout<<"Equal"<<endl;
}
int main() {
int n = 231, m = 337, k = 3;
solve(n, m, k);
return 0;
}Input
231, 337, 3
Output
Second
Updated on: 29-Mar-2022
361 Views
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