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Convert a given Binary tree to a tree that holds Logical AND property on C++
In this tutorial, we will be discussing a program to convert a given Binary tree to a tree that holds Logical AND property.
For this we will be provided with a binary tree. Our task is to convert it into a tree that holds the logical AND property means that a node has a value of the AND operation of its children nodes. Note that every node can have a value either zero or one.
Example
#include<bits/stdc++.h>
using namespace std;
//node structure of binary tree
struct Node{
int data;
struct Node* left;
struct Node* right;
};
//creation of a new node
struct Node* newNode(int key){
struct Node* node = new Node;
node->data= key;
node->left = node->right = NULL;
return node;
}
//converting the tree with nodes following
//logical AND operation
void transform_tree(Node *root){
if (root == NULL)
return;
//moving to first left node
transform_tree(root->left);
//moving to first right node
transform_tree(root->right);
if (root->left != NULL && root->right != NULL)
root->data = (root->left->data) &
(root->right->data);
}
//printing the inorder traversal
void print_tree(Node* root){
if (root == NULL)
return;
print_tree(root->left);
printf("%d ", root->data);
print_tree(root->right);
}
int main(){
Node *root=newNode(0);
root->left=newNode(1);
root->right=newNode(0);
root->left->left=newNode(0);
root->left->right=newNode(1);
root->right->left=newNode(1);
root->right->right=newNode(1);
printf("Before conversion :\n");
print_tree(root);
transform_tree(root);
printf("\nAfter conversion :\n");
print_tree(root);
return 0;
}Output
Before conversion : 0 1 1 0 1 0 1 After conversion : 0 0 1 0 1 1 1
Updated on: 06-Jan-2020
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