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C++ Program to Check Whether a Given Tree is Binary Search Tree
Binary Search Tree is a binary tree data structure in which we have 3 properties
The left subtree of a binary search tree of a node contains only nodes with keys lesser than the node’s key.
The right subtree of a binary search tree node contains only nodes with keys greater than the node’s key.
The left and right trees of a subtree each must also be a binary search tree.
Algorithm
Begin function BSTUtill() If node is equals to NULL then Returns 1. If data of node is less than minimum or greater than maximum data then Return 0. Traverse left and right sub-trees recursively. End.
Example Code
#include <iostream>
#include <cstdlib>
#include <climits>
using namespace std;
struct n {
int d;
n* l;
n* r;
};
int BSTUtil(n* node, int min, int max);
int isBST(n* node) {
return(BSTUtil(node, INT_MIN, INT_MAX));
}
int BSTUtil(struct n* node, int min, int max) {
if (node==NULL)
return 1;
if (node->d < min || node->d > max)
return 0;
return BSTUtil(node->l, min, node->d - 1) && BSTUtil(node->r, node->d + 1, max);
}
n* newN(int d) {
n* nod = new n;
nod->d = d;
nod->l = NULL;
nod->r = NULL;
return nod;
}
int main() {
n *root = newN(7);
root->l = newN(6);
root->r = newN(10);
root->l->l = newN(2);
root->l->r = newN(4);
if (isBST(root))
cout<<"The Given Tree is a BST"<<endl;
else
cout<<"The Given Tree is not a BST"<<endl;
n *root1 = newN(10);
root1->l = newN(6);
root1->r = newN(11);
root1->l->l = newN(2);
root1->l->r = newN(7);
if (isBST(root1))
cout<<"The Given Tree is a BST"<<endl;
else
cout<<"The Given Tree is not a BST"<<endl;
return 0;
}Output
The Given Tree is not a BST The Given Tree is a BST
Updated on: 30-Jul-2019
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