Convert a Binary Tree to Threaded binary tree | Set 1 (Using Queue) in C++

C++Server Side ProgrammingProgramming

In this tutorial, we will be discussing a program to convert a binary tree to a threaded binary tree using a queue data structure.

For this, we will be provided with a binary tree. Our task is to convert that particular binary tree into a threaded binary tree by adding additional routes for quicker inorder traversal with the help of a queue data structure.


 Live Demo

#include <iostream>
#include <queue>
using namespace std;
//node structure for threaded tree
struct Node {
   int key;
   Node *left, *right;
   bool isThreaded;
//putting the inorder pattern into a queue
void convert_queue(Node* root, std::queue<Node*>* q){
   if (root == NULL)
   if (root->left)
      convert_queue(root->left, q);
   if (root->right)
      convert_queue(root->right, q);
//traversing the queue and making threaded tree
void create_threadedtree(Node* root, std::queue<Node*>* q){
   if (root == NULL)
   if (root->left)
      create_threadedtree(root->left, q);
   if (root->right)
      create_threadedtree(root->right, q);
   //if right pointer in NUll, point it to
   //inorder successor
   else {
      root->right = q->front();
      root->isThreaded = true;
//finally taking the tree and converting it into threaded
void createThreaded(Node* root){
   std::queue<Node*> q;
   convert_queue(root, &q);
   create_threadedtree(root, &q);
Node* leftMost(Node* root){
   while (root != NULL && root->left != NULL)
      root = root->left;
      return root;
   //performing inorder traversal of threaded tree
   void inOrder(Node* root){
      if (root == NULL)
      Node* cur = leftMost(root);
      while (cur != NULL) {
         cout << cur->key << " ";
         //if threaded node, move to inorder successor
         if (cur->isThreaded)
            cur = cur->right;
            cur = leftMost(cur->right);
   Node* newNode(int key){
      Node* temp = new Node;
      temp->left = temp->right = NULL;
      temp->key = key;
      return temp;
int main(){
   Node* root = newNode(1);
   root->left = newNode(2);
   root->right = newNode(3);
   root->left->left = newNode(4);
   root->left->right = newNode(5);
   root->right->left = newNode(6);
   root->right->right = newNode(7);
   cout << "Traversing threaded tree :\n";
   return 0;


Traversing threaded tree :
4 2 5 1 6 3 7
Published on 02-Jan-2020 10:22:44