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Check whether the length of given linked list is Even or Odd in Python
Suppose we have a linked list, we have to check whether the length of it is odd or even.
So, if the input is like head = [5,8,7,4,3,6,4,5,8], then the output will be Odd.
To solve this, we will follow these steps −
- while head is not null and next of head is not null, do
- head := next of next of head
- if head is null, then
- return "Even"
- return "Odd"
Let us see the following implementation to get better understanding −
class ListNode: def __init__(self, data, next = None): self.val = data self.next = next def make_list(elements): head = ListNode(elements) for element in elements[1:]: ptr = head while ptr.next: ptr = ptr.next ptr.next = ListNode(element) return head def solve(head): while head != None and head.next != None: head = head.next.next if head == None: return "Even" return "Odd" head = make_list([5,8,7,4,3,6,4,5,8]) print(solve(head))
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