Check whether given floating point number is even or odd in Python

Suppose we have a floating point number; we have to check whether the number is odd or even. In general, for integer it is easy by dividing the last digit by 2. But for floating point number it is not straight forward like that. We cannot divide last digit by 2 to check if it is odd or even.

So, if the input is like n = 200.290, then the output will be Odd though the last digit is divisible by 2.

To solve this, we will follow these steps −

• s := convert number as string
• flag := False
• for i in range size of s - 1 to 0, decrease by 1, do
  • if s[i] is '0' and flag is False, then
    • go for next iteration
  • if s[i] is same as '.', then
    • flag := True
    • go for next iteration
  • if s[i] is even, then
    • return "Even"
  • return "Odd"

Let us see the following implementation to get better understanding −

Example Code

Live Demo

def solve(n) :
   s = str(n)

   flag = False
   for i in range(len(s) - 1, -1, -1) :
      if s[i] == '0' and flag == False :
         continue
  
      if s[i] == '.':
         flag = True
         continue
        
      if int(s[i]) % 2 == 0 :
         return "Even"
           
      return "Odd"    

n = 200.290
print(solve(n))

Input

200.290

Output

Odd

Arnab Chakraborty

Updated on 16-Jan-2021 04:29:44

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