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Java Program to Check Whether a Number is Even or Odd
In this article, we will understand how to check whether a number is even or odd. This is accomplished by checking if the given number is divisible by 2.
Below is a demonstration of the same −
Input
Suppose our input is −
Enter the number : 45
Output
The desired output would be −
The number 45 is an odd number
Algorithm
Step 1 - START Step 2 - Declare an integer values namely my_input. Step 3 - Read the required values from the user/ define the values Step 4 - Use the modulus operator and compute my_input % 2 value. Step 5 - If the result is 0, then its an even number, else it’s an odd number. Step 5 - Display the result Step 6 - Stop
Example 1
Here, the input is being entered by the user based on a prompt. You can try this example live in our coding ground tool 
.
import java.util.Scanner;
public class EvenOdd {
public static void main(String[] args) {
int my_input;
System.out.println("Required packages have been imported");
Scanner my_scanner = new Scanner(System.in);
System.out.println("A reader object has been defined ");
System.out.print("Enter the number : ");
my_input = my_scanner.nextInt();
if(my_input % 2 == 0)
System.out.println("The number " +my_input + " is an even number");
else
System.out.println("The number " +my_input + " is an odd number");
}
}Output
Required packages have been imported A reader object has been defined Enter the number : 45 The number 45 is an odd number
Example 2
Here, the integer has been previously defined, and its value is accessed and displayed on the console.
public class EvenOdd {
public static void main(String[] args) {
int my_input;
my_input = 45;
System.out.println("The number is defined as " +my_input);
if(my_input % 2 == 0)
System.out.println("The number " +my_input + " is an even number");
else
System.out.println("The number " +my_input + " is an odd number");
}
}Output
The number is defined as 45 The number 45 is an odd number
Updated on: 22-Feb-2022
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