Calculate n + nn + nnn + u + n(m times) in Python Program

In this tutorial, we are going to write code to find the sum of the series n + nn + nnn + ... + n (m times). We can do it very easily in Python. Let's see some examples.

Input:
n = 1
m = 5
Series:
1 + 11 + 111 + 1111 + 11111
Output:
12345

Algorithm

Follow the below steps to solve the problem.

1. Initialise the n and m.
2. Initialise total to 0.
3. Make the copy of n to generate next number in the series.
4. Iterate the loop m times.
   4.1. Add n to the total.
   4.2. Update the n with n * 10 + copy_n.
5. Print the total.

Example

See the code below.

 Live Demo

# initializing n and m
n = 1
m = 5
# initializing total to 0
total = 0
# making the copy of n to get next number in the series
copy_n = n
# iterating through the loop
for i in range(m):
   # adding n to total
   total += n
   # updating n to get next number in the serias
   n = n * 10 + copy_n
# printing the total
print(total)

Output

If you run the above code, you will get the following results.

12345

Conclusion

If you have any doubts in the article, mention them in the comment section.