Calculate n + nn + nnn + … + n(m times) in Python program

PythonServer Side ProgrammingProgramming

We are going to write a program that calculates the following series in Python. Examine the example inputs and outputs for the program that we are going to write.

Input:
34
3 + 33 + 333 + 3333
Output:
3702


Input:
5 5 5 + 55 + 555 + 5555 + 55555
Output:
61725

So, we will have two numbers, and we have to calculate the sum of the series generated as above. Follow the below steps to achieve the output.

Algorithm

1. Initialize the number let's say n and m.
2. Initialize a variable with the value n let's say change.
3. Intialize a variable s to zero.
4. Write a loop which iterates m times.
   4.1. Add change to the s.
   4.2. Update the value of change to get next number in the series.
5. Print the sum at the end of the program.

You have to create a general formula to generate numbers in the series. Try to get it as your own. If you stuck at the logic, see the code below.

Example

## intializing n and m
n, m = 3, 4
## initializing change variable to n
change = n
## initializing sum to 0
s = 0
## loop
for i in range(m):
   ## adding change to s
   s += change
   ## updating the value of change
   change = change * 10 + n
## printing the s
print(s)

Output

If you run the above program, you will get the following output.

3702

Let's see another example with different values as we discussed in the examples.

Example

## intializing n and m
n, m = 5, 5
## initializing change variable to n
change = n
## initializing sum to 0
s = 0
## loop
for i in range(m):
   ## adding change to s
   s += change
   ## updating the value of change
   change = change * 10 + n
## printing the s
print(s)

Output

If you run the above program, you will get the following output.

61725

Conclusion

If you have any doubts regarding the tutorial, mention them in the comment section.

raja
Published on 23-Oct-2019 11:38:59
Advertisements