# Big Numbers in Python

Suppose we have a matrix, we have to find the total number of integers whose value is the largest in its row and column.

So, if the input is like

 1 3 2 4 6 5 1 5 7

then the output will be 2 as 6 and 7 are valid.

To solve this, we will follow these steps −

• mat := matrix

• r_maxes := make a list of max elements of each row of mat

• c_maxes := make a list of max elements of each column of mat

• a := a new list

• for r in range 0 to number of rows - 1, do

• for c in range 0 to number of columns - 1, do

• v := mat[r, c]

• if r_maxes[r] is v and c_maxes[c] is v, then

• insert v at the end of a

• return size of a

Let us see the following implementation to get better understanding −

## Example

Live Demo

class Solution:
def solve(self, matrix):
mat = matrix
trans_mat = list(zip(*matrix))
print(mat, trans_mat)
r_maxes = [max(row) for row in mat]
c_maxes = [max(t_row) for t_row in trans_mat]
a = []
for r in range(len(mat)):
for c in range(len(trans_mat)):
v = mat[r][c]
if (r_maxes[r], c_maxes[c]) == (v, v):
a.append(v)
return len(a)
ob = Solution()
matrix = [
[1, 3, 2],
[4, 6, 5],
[1, 5, 7]
]
print(ob.solve(matrix))

## Input

[[1, 3, 2], [4, 6, 5], [1, 5, 7]]

## Output

2

Updated on: 02-Sep-2020

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