Big Numbers in Python

Suppose we have a matrix, we have to find the total number of integers whose value is the largest in its row and column.

So, if the input is like

then the output will be 2 as 6 and 7 are valid.

To solve this, we will follow these steps −

• mat := matrix

• r_maxes := make a list of max elements of each row of mat

• c_maxes := make a list of max elements of each column of mat

• a := a new list

• for r in range 0 to number of rows - 1, do

  • for c in range 0 to number of columns - 1, do

    • v := mat[r, c]

    • if r_maxes[r] is v and c_maxes[c] is v, then

      • insert v at the end of a

• return size of a

Let us see the following implementation to get better understanding −

Example

 Live Demo

class Solution:
   def solve(self, matrix):
      mat = matrix
      trans_mat = list(zip(*matrix))
      print(mat, trans_mat)
      r_maxes = [max(row) for row in mat]
      c_maxes = [max(t_row) for t_row in trans_mat]
      a = []
      for r in range(len(mat)):
         for c in range(len(trans_mat)):
            v = mat[r][c]
            if (r_maxes[r], c_maxes[c]) == (v, v):
               a.append(v)
      return len(a)
ob = Solution()
matrix = [
   [1, 3, 2],
   [4, 6, 5],
   [1, 5, 7]
]
print(ob.solve(matrix))

Input

[[1, 3, 2], [4, 6, 5], [1, 5, 7]]

Output

2

Arnab Chakraborty

Updated on: 02-Sep-2020

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