Server Side Programming Articles - Page 1907 of 2650

Suppose we have an expression. The expression has some parentheses; we have to check the parentheses are balanced or not. The order of the parentheses are (), {} and []. Suppose there are two strings. “()[(){()}]” this is valid, but “{[}]” is invalid.To solve this, we will follow these steps −Traverse through the expression until it has exhaustedif the current character is opening bracket like (, { or [, then push into stackif the current character is closing bracket like ), } or ], then pop from stack, andcheck whether the popped bracket is corresponding starting bracket of thecurrent character, ... Read More

Suppose we have a non-negative integer number num. For each number i in the range 0 ≤ i ≤ num we have to calculate the number of 1's in their binary counterpart and return them as a list. So if the number is 5, then the numbers are [0, 1, 2, 3, 4, 5], and number of 1s in these numbers are [0, 1, 1, 2, 1, 2]To solve this, we will follow these steps −res := an array which holds num + 1 number of 0soffset := 0for i in range 1 to num + 1if i and i ... Read More

Suppose there is a list of non-negative integers, we have to arrange them such that they form the largest number. So if the array is [10, 2], then the largest number will be 210.To solve this, we will follow these steps −Arrange the numbers where the most significant digits are greater than place them at first, like this arrangement the numbers. After that just join the numbers from the array.ExampleLet us see the following implementation to get a better understanding − Live Demofrom functools import cmp_to_key class Solution(object):    def largestNumber(self, nums):       for i in range(len(nums)):     ... Read More

Suppose we have Reverse polish notation and we have to evaluate the value. The reverse polish notation is also known as postfix expression. Here we have to use the stack data structure to solve the postfix expressions.From the postfix expression, when some operands are found, pushed them in the stack. When some operator is found, two items are popped from stack and then the operation is performed in the correct sequence. After that, the result is also pushed in the stack for future use. After completing the whole expression, the final result is also stored in the stack top. So ... Read More

Suppose we have one non-empty string s and a dictionary wordDict. That is containing a list of non-empty words, determine when s can be segmented into a space-separated sequence of one or more dictionary words. We have to follow some rules −The same word in the dictionary may be reused multiple numbers of times in the segmentation.We can assume that the dictionary does not contain duplicate words.Suppose the string s = “applepenapple”, and word dictionary is like [“apple”, “pen”], then the output will be true because the string s can be segmented as “apple pen apple”.Let us see the steps ... Read More

Suppose there is a circle, and there are n gas stations on the circle. We have two sets of data like −The amount of gas that every gas stations hasDistance from one gas stations to another.Calculate the first point, from where a car will be able to complete the circle. Assume for 1 unit of gas, the car can go 1 unit of distance. Suppose there are four gas stations, and the amount of gas, and distance from the next gas stations is as like [(4, 6), (6, 5), (7, 3), (4, 5)], the first point from where car can ... Read More

Suppose we have one input string, a partitioning of that string is palindrome partitioning, when every substring of the partition is a palindrome. In this section, we have to find the minimum cuts are needed to palindrome partitioning the given string. So if the string is like “ababbbabbababa” Minimum cut to partition as palindrome. Here 3 cuts are needed. The palindromes are: a | babbbab | b | ababaTo solve this, we will follow these steps −n := length of strdefine cut matrix and pal matrix each of order n x nfor i := 0 to n, dopal[i, i] := ... Read More

Suppose we have a triangle. We have to find the minimum path sum from top to the bottom. In each step we can move to adjacent numbers on the row below.For example, if the following triangle is like[    [2],    [3, 4],    [6, 5, 7],    [4, 1, 8, 3] ]The minimum path sum from top to bottom is 11 (2 + 3 + 5 + 1 = 11).Let us see the stepsCreate one table to use in Dynamic programming approach.n := size of trianglefor i := n – 2 down to 0for j := 0 to idp[j] ... Read More

Suppose we have a binary tree. We have to traverse this tree using the level order traversal scheme. So if the tree is likeThe traversal sequence will be like − [10, 5, 16, 8, 15, 20, 23]To solve this, we will follow these steps −define queue que to store nodesinsert root into the que.while que is not empty, doitem := item present at front position of queueprint the value of itemif left of the item is not null, then insert left of item into queif right of the item is not null, then insert right of item into quedelete front ... Read More

Suppose we have a binary tree. We have to traverse this tree using the inorder traversal scheme without using recursion. So if the tree is likeThen the traversal will be [2, 5, 7, 10, 15, 20]To solve this, we will follow these steps −Create two array res and stack, set curr := rootRun one infinite loopwhile current is not nullpush curr into a stack, and set curr := left of currwhen the length of stack = 0, then return resnode := popped element from the stackinsert a value of node into rescurr := right of currExampleLet us see the following ... Read More