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Found 33676 Articles for Programming

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You can simply iterate through list and fill the array as shown below −import java.util.ArrayList; import java.util.List; public class Tester { public static void main(String[] args) { List list = new ArrayList(); list.add(new Integer(1)); list.add(new Integer(2)); list.add(new Integer(3)); list.add(new Integer(4)); int[] array = new int[list.size()]; for(int i=0;i

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Yes. From Java 8 onwards, we can do so using method references.Method references help to point to methods by their names. A method reference is described using "::" symbol. A method reference can be used to point the following types of methods −Static methodsInstance methodsConstructors using new operator (TreeSet::new)Method Reference ExampleCreate the following Java program using any editor of your choice in, say, C:\> JAVA.Java8Tester.java Live Demo import java.util.List; import java.util.ArrayList; public class Java8Tester { public static void main(String args[]) { List names = new ArrayList(); names.add("Mahesh"); names.add("Suresh"); names.add("Ramesh"); ... Read More

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A method can give multiple values if we pass an object to the method and then modifies its values. See the example below −Examplepublic class Tester { public static void main(String[] args) { Model model = new Model(); model.data1 = 1; model.data2 = 2; System.out.println(model.data1 + ", " + model.data2); changeValues(model); System.out.println(model.data1 + ", " + model.data2); } public static void changeValues(Model model) { model.data1 = 100; model.data2 = 200; } } class Model { int data1; int data2; }Output1, 2 100, 200

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Call by Value means calling a method with a parameter as value. Through this, the argument value is passed to the parameter.While Call by Reference means calling a method with a parameter as reference. Through this, the argument reference is passed to the parameter.In call by value, the modification done to the parameter passed does not reflect in the caller's scope while in call by reference, the the modification done to the parameter passed are persistent and changes are reflected in the caller's scope.But Java uses only call by value. It creates a copy of references and pass them as ... Read More

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Yes, break statement can be used in nested for loops. It works on the for loop in which it is applied. See the example below.Examplepublic class Tester { public static void main(String[] args) { for(int i = 0; i< 2; i++) { for(int j = 0; j < 2; j++){ if(i == 1) { break; } System.out.println("i = " + i+",j = " + j); } } } }

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Use List.clear() method to empty an array.Exampleimport java.util.ArrayList; import java.util.List; public class Tester { public static void main(String[] args) { List list = new ArrayList(); list.add("A"); list.add("B"); list.add("C"); list.add("D"); list.add("E"); list.add("F"); list.add("G"); list.add("H"); System.out.println("Original List " + list); list.clear(); System.out.println("Cleared List " + list); } }OutputOriginal List [A, B, C, D, E, F, G, H] Cleared List []

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In this article, we will learn to create an array of objects in Java. An array of Object classes can be created that can accept any type of object. During the operation on such an array, instanceof operator can be used. Different Approaches The following are the two different approaches to creating an array of objects in Java − Using an Object[] Array Using a Class-Specific Object Array Using an Object[] Array Java provides a built-in Object class, which is the superclass of all classes. This means an array ... Read More

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Following example uses Contains method to search a String in the Array.Exampleimport java.util.ArrayList; public class Main { public static void main(String[] args) { ArrayList objArray = new ArrayList(); ArrayList objArray2 = new ArrayList(); objArray2.add(0, "common1"); objArray2.add(1, "common2"); objArray2.add(2, "notcommon"); objArray2.add(3, "notcommon1"); objArray.add(0, "common1"); objArray.add(1, "common2"); System.out.println("Array elements of array1"+objArray); System.out.println("Array elements of array2"+objArray2); System.out.println("Array 1 contains String common2?? " +objArray.contains("common1")); System.out.println("Array 2 contains Array1?? " +objArray2.contains(objArray) ); } }OutputThe above code sample will produce the following result.Array elements of array1[common1, common2] Array elements of array2[common1, common2, notcommon, notcommon1] Array ... Read More