Programming Articles - Page 1787 of 3366

To check if a string is a valid keyword in Java, the code is as follows −Example Live Demoimport java.util.*; public class Demo{    static boolean valid_identifier(String my_str, int n){       if (!((my_str.charAt(0) >= 'a' && my_str.charAt(0) = 'A' && my_str.charAt(1) = 'a' && my_str.charAt(i) = 'A' && my_str.charAt(i) = '0' && my_str.charAt(i)

OpenCSV has to be installed first, which is a parser library for Java. The dependency has to be mentioned in the pom.xml file in the maven project. After that, the below code can be utilized.Exampleimport java.io.FileReader; import java.io.*; public class Demo{    public static void readDataLineByLine(String file){       try{          FileReader my_filereader = new FileReader(file);          CSVReader csvReader = new CSVReader(my_filereader);          String[] nextRecord;          while ((nextRecord = csvReader.readNext()) != null){             for (String cell : nextRecord){         ... Read More

Class variables are also known as static variables, and they are declared outside a method, with the help of the keyword ‘static’.Static variable is the one that is common to all the instances of the class. A single copy of the variable is shared among all objects.Example Live Demopublic class Demo{    static int my_count=2;    public void increment(){       my_count++;    }    public static void main(String args[]){       Demo obj_1=new Demo();       Demo obj_2=new Demo();       obj_1.increment();       obj_2.increment();       System.out.println("The count of first object is "+obj_1.my_count); ... Read More

An object graph contains a set of objects that are automatically serialized given that the object that contains the reference is serialized too. Any object that is serialized and contains an object reference, the object reference will be serialized by the JVM.Example Live Demoimport java.io.FileInputStream; import java.io.FileOutputStream; import java.io.ObjectInputStream; import java.io.ObjectOutputStream; import java.io.Serializable; class One implements Serializable{    Two s2 = new Two(); } class Two implements Serializable{    Three s3 = new Three(); } class Three implements Serializable{    int i = 34;    int j = 67; } public class Demo_Serialize{    public static void main(String args[]) throws Exception{ ... Read More

Blockchain has become a buzz word in the recent times. It is being tried to be implemented in every software for various purposes, to check how it would work efficiently given different scenarios. It is a decentralized technology. It basically is data that is digital in nature and every piece of data is known as a transaction. Hence, the date, time and amount of that specific transaction is stored in the blockchain. Every block is unique due to the unique code it has, that is also known as ‘hash’. It is created with the help of different specialized algorithms.Investors are ... Read More

Given the task is to find the maximum number without any leading or trailing zeroes or ones whose product of factorial of its digits is equal to the product of factorial of digits of the given number N.Let’s now understand what we have to do using an example −Input − N = 4912Output − 73332222Explanation − 4! * 9! * 1! * 2! = 7! * 3! * 3! * 3! * 2! * 2! *2! *2! = 17, 418, 240Input − N = 340Output − 3322Approach used in the below program as followsIn order to attain the maximum answer ... Read More

Once the byte code is loaded by the JVM, (with the help of the .class file), the bytecode is checked to see the validity with the help of the verifier. The verifier checks the linking so as to perform operations efficiently. This way, the interpreter performs much efficiently. This process is known as verification.Example Live Demopublic class Demo{    private float my_val;    float my_function(int my_val){       int balance = my_val;       this.my_val += balance;       return this.my_val;    }    public static void main(String[] args){       Demo my_obj = new Demo();   ... Read More

Given the task is to find the maximum number that can be displayed using N segment on ant number of seven segment display.Let’s now understand what we have to do using an example −Input − N=5Output − 71Explanation − The largest number will be displayed as follows on the seven segment display −Input − N=6Output − 111Approach used in the below program as followsThe following situation can be divided into 3 case −Case 1 −If N is 0 or 1, then it is not possible to display any number.Case 2 −If N is odd. Then the numbers that can be ... Read More

Given the task is to find the maximum number of Zombie processes that a system can handle or in other words, the program does not stop its execution.A Zombie process (also known as defunct process) is a process that has completed its process via exit() (system call) but still has an entry in the process table.Approach used in the below program as followsNote that should be added in order to run the program.In main() function initialize num = 0 of type int which we will iterate until the program stops being executed.To initiate a zombie process create a while statement ... Read More

In this problem, we are given three numbers a, b, and M. our task is to create a program to find the sum of two numbers modulo M.Let’s take an example to understand the problem, Input: a = 14 , b = 54, m = 7 Output: 5 Explanation: 14 + 54 = 68, 68 % 7 = 5To solve this problem, we will simply add the numbers a and b. And then print the remainder of the sum when divided by M.ExampleProgram to illustrate the working of our solution,  Live Demo#include using namespace std; int moduloSum(int a, int ... Read More