Suppose we have two strings S and T. We have to check whether S is subsequence of T or not.So, if the input is like S = "abc", T = "adbrcyxd", then the output will be TrueTo solve this, we will follow these steps −if s is same as t, then −return truen := size of s, m := size of tj := 0for initialize i := 0, when i < n, update (increase i by 1), do −if t[j] is same as s[i], then −(increase j by 1)if j is same as size of t, then −return truereturn falseLet ... Read More

Suppose we have a list of numbers called nums, we have to check whether there is a sublist such that its sum is strictly greater than the total sum of the list.So, if the input is like nums = [1, −2, 3, 4], then the output will be True, as the sum of the list is 6 and the sum of the sublist [3, 5] is 8 which is strictly larger.To solve this, we will follow these steps −total := sum of elements numss := 0for each i in nums, dos := s + iif s < 0, thenreturn Trues ... Read More

Suppose we have two numbers as string. We have to multiply them and return the result also in string. So if the numbers are “28” and “25”, then the result will be “700”To solve this, we will follow these steps −Taking two arguments x and y it indicates x divides yif x < −Infinity and y = 1, then return infinitya := |x|, b := |y| and ans := 0while a − b >= 0p := 0while a − (left shifted b (left shifted 1 p times)) >= 0p := p + 1a := a − (left shift b, p ... Read More

Suppose we have a list of stacks, we can take any stack or stacks and pop any number of elements from it. We have to find the maximum sum that can be achieved such that all stacks have the same sum value.So, if the input is like stacks = [[3, 4, 5, 6], [5, 6, 1, 4, 4], [10, 2, 2, 2] ], then the output will be 12, as we can take operations like −Pop [6] from the first stack we get [3, 4, 5] the sum is 12.Pop [4, 4] from the second stack we get [5, 6, ... Read More

Suppose we have a number n, we have to find two or more numbers such that their sum is equal to n, and the product of these numbers is maximized, we have to find the product.So, if the input is like n = 12, then the output will be 81, as 3 + 3 + 3 + 3 = 12 and 3 * 3 * 3 * 3 = 81.To solve this, we will follow these steps −Define a function dp() . This will take nif n is same as 0, thenreturn 1ans := 0for i in range 1 to ... Read More

Suppose, we have an array A with few integers. We have to sort the numbers as even then odd. So put the even numbers at first, then the odd numbers. So if the array is like A = [1, 5, 6, 8, 7, 2, 3], then the result will be like [6, 8, 2, 1, 5, 7, 3]To solve this, we will follow these steps −set i := 0 and j := 0while j < size of arrif arr[j] is even, thenswap arr[i] and arr[j], increase i by 1increase j by 1return arrLet us see the following implementation to get ... Read More

Suppose we have a 2D matrix where each row is sorted in ascending order. We have to find the smallest number that exists in every row. If there's no such result, then return −1.So, if the input is like23551010135then the output will be 5To solve this, we will follow these steps −if matrix is empty, thenreturn −1first := a new set from first row of matrixfor each row in matrix, dofirst := Intersect first a set of elements of rowif first is empty, thenreturn −1return minimum of firstLet us see the following implementation to get better understanding −Example Live Democlass Solution: ... Read More

Suppose we have a value k and a binary search tree, here each node is either a leaf or contains 2 children. We have to find the node containing the value k, and return its sibling's value.So, if the input is likek = 4., then the output will be 10.To solve this, we will follow these steps −Define a function util() . This will take root, k, ansif left of root is not null and right of root is not null, thenreturnif k > value of root, thenif value of right of root is same as k, theninsert value of ... Read More

Suppose we have a list of numbers called nums, we have to check whether we can divide the list into two groups A and B such that: The sum of A and the sum of B are same. Here every number in A is strictly smaller than every number in B.So, if the input is like nums = [3, 4, 5, 12], then the output will be True, as we can have A = [3, 4, 5] and B = [12] and both have sum 12.To solve this, we will follow these steps −sort the list numstotal := sum of ... Read More

Suppose we have a number num. For each numbers i in the range 0 ≤ i ≤ num we have to calculate the number of 1's in their binary counterpart and return them as a list. So if the number is 5, then the numbers are [0, 1, 2, 3, 4, 5], and number of 1s in these numbers are [0, 1, 1, 2, 1, 2], so it will return 7.To solve this, we will follow these steps −res := an array which holds num + 1 number of 0soffset := 0for i in range 1 to num + 1if ... Read More