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Replace Elements with Greatest Element on Right Side in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 480 Views

Suppose we have an array A. We have to replace every element by the greatest element on the right side of this element. And replace the last one by -1. So if A = [5, 17, 40, 6, 3, 8, 2], then it will be [40,40,8,8,8,2,-1]To solve this, we will follow these steps −We will read the array element from right to left.take e := -1for i := n – 1 to 0temp := ee := max between e and array[i]array[i] := tempreturn arrayExampleLet us see the following implementation to get better understanding −#include using namespace std; void print_vector(vector v){    cout

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Maximum element in min heap in C++

Narendra Kumar
Narendra Kumar
Updated on 11-Mar-2026 411 Views

Problem statementGiven a minimum heap find maximum element in that.ExampleIf input heap is −Then maximum element is 55AlgorithmIn minimum heap parent node will be lesser than its children. Hence we can conclude that a non-leaf node cannot be the maximum.Search maximum element in the leaf nodesExampleLet us now see an example −#include using namespace std; int getMaxElement(int *heap, int n) {    int maxVal = heap[n / 2];    for (int i = n / 2 + 1; i < n; ++i) {       maxVal = max(maxVal, heap[i]);    }    return maxVal; } int main() {    int heap[] = {15, 27, 22, 35, 29, 55, 48}; int n = sizeof(heap) / sizeof(heap[0]);    cout

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Range Sum Query - Immutables in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 258 Views

Suppose we have an array of integers. We have to find the sum of the elements present from index i to j. Two things we have to keep in mind that the array will be immutable, so elements will not be altered, and there will be multiple such queries. So we have to care about the execution time for a large number of queries. Suppose the array is like A = [5, 8, 3, 6, 1, 2, 5], then if query is (A, 0, 3), then it will be 5 + 8 + 3 + 6 = 22.To solve this, ...

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Convert array into Zig-Zag fashion in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 411 Views

In this tutorial, we will be discussing a program to convert an array into zig-zag fashion.For this we will be provided with an array containing distinct elements. Our task is to rearrange the elements of the given array in a zig zag fashion with greater and smaller elements alternatively as compared to the previous element.Example#include using namespace std; //converting into zig-zag fashion void convert_zigzag(int arr[], int n) {    //flag denotes the greater or smaller relation    bool flag = true;    for (int i=0; i arr[i+1])          swap(arr[i], arr[i+1]);       } else { ...

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Find N Unique Integers Sum up to Zero in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 407 Views

Suppose we have an integer n. We have to return any array that contains n unique integers, such that they add up to 0. So if input is n = 5, then one possible output will be [-7, -1, 1, 3, 4]To solve this, we will follow these steps −take an array A as final answer, and take x := 0for i in range 0 to n – 2A[i] = (i + 1)x := x + i + 1A[n – 1] = xreturn AExampleLet us see the following implementation to get better understanding −#include using namespace std; void print_vector(vector v){    cout

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Product of all Subsequences of size K except the minimum and maximum Elements in C++

Sunidhi Bansal
Sunidhi Bansal
Updated on 11-Mar-2026 260 Views

Given an array arr[n], containing n number of integers and an integer k for defining the size; the task is to print the product of all the subsequences of size k except the minimum and maximum elements.Let us assume we have a set of 4 elements {1, 2, 3, 4} and k as 2 so its subsets will be − {1, 2}, {2, 3}, {3, 4}, {1, 4}, {1, 3}, {2, 4}So excluding the maximum element 4, and minimum element 1, the remaining elements will be −2, 3, 3, 3, 2, product of which will be −2 * 3 * ...

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Maximum 0's between two immediate 1's in binary representation in C++

Narendra Kumar
Narendra Kumar
Updated on 11-Mar-2026 924 Views

Problem statementGiven a number n, the task is to find the maximum 0’s between two immediate 1’s in binary representation of given n. Return -1 if binary representation contains less than two 1’sExampleIf input number is 35 then its binary representation is −00100011In above binary representation there are 3 0’s between two immediate 1’s. Hence answer is 3.AlgorithmWe can use bitwise shift operator to solve this problem. We need to find the position of two immediate 1’s in binary representation of n and maximize the difference of these position.If number is 0 or power of 2 then return -1IInitialize variable ...

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Power of Three in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 2K+ Views

Suppose we have a number n. We have to check whether the number is the power of 3 or not. So if the number is like n = 27, that is the power of 3, the result will be true, if n = 15, it will be false.To solve this, we will follow these steps −We will use the Logarithm to solve thisif [log10(n) / log10(3)] mod 1 == 0, then it will be power of three, otherwise notExampleLet us see the following implementation to get a better understanding −class Solution(object):    def isPowerOfThree(self, n):       """       :type n: int       :rtype: bool       """       if not n or n

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Reverse String in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 2K+ Views

Suppose we have an array of characters. We have to reverse the string without using any additional space. So if the string is like [‘H’, ‘E’, ‘L’, ‘L’, ‘O’], the output will be [‘O’, ‘L’, ‘L’, ‘E’, ‘H’]To solve this, we will follow these steps −Take two pointers to start = 0 and end = length of the string – 1swap first and last charactersincrease start by 1 and decrease-end by 1ExampleLet us see the following implementation to get a better understanding −class Solution(object):    def reverseString(self, s):       """       :type s: List[str]     ...

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Convert BST to Max Heap in C++

Ayush Gupta
Ayush Gupta
Updated on 11-Mar-2026 642 Views

In this tutorial, we will be discussing a program to convert a binary search tree to a max heap.For this we will be provided with a binary search tree. Our task is to convert the given binary search tree into a max heap such that following the condition of the binary search tree when elements are compared with themselves.Example#include using namespace std; //node structure of BST struct Node {    int data;    Node *left, *right; }; //node creation struct Node* getNode(int data) {    struct Node* newNode = new Node;    newNode->data = data;    newNode->left = newNode->right ...

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