Programming Articles

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How to check whether a column value is less than or greater than a certain value in R?

Nizamuddin Siddiqui
Nizamuddin Siddiqui
Updated on 11-Mar-2026 2K+ Views

To check whether a column value is less than or greater than a certain value, we can use with function and the output will be a logical vector representing values with TRUE when the condition is satisfied and FALSE when the condition is not satisfied. For example, if we have a column say x of an R data frame df and we want to check whether any of the values in x is greater than 10 or not then it can be done by using with(df, df$x>10).ExampleConsider the below data frame:> set.seed(1002) > x1 y1 z1 df1 df1Outputx1 y1 z1 ...

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How to create an arrow in base R?

Nizamuddin Siddiqui
Nizamuddin Siddiqui
Updated on 11-Mar-2026 2K+ Views

To create an arrow R, we can use plot function and arrows function. We just need to understand all the coordinate values that should be passed inside the arrows function. For example, if we have two vectors that contains values from 1 to 10 then the arrow can be created by using arrows function as arrows(1,1,10,10).Example> x y plot(x,y)OutputExample> arrows(1,1,10,10)Output

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How to remove ticks in a plot created by using gglot2 in R?

Nizamuddin Siddiqui
Nizamuddin Siddiqui
Updated on 11-Mar-2026 279 Views

In a plot created by using ggplot2, the axes values are generated with tick marks such as representing X-axis labels from 1 to 10 and Y-axis labels from 10 to 1 but we can get rid of this tick marks by using theme function. If we want to create a plot without ticks then we just need to add the following code to the plot code.theme(axis.ticks.x=element_blank(), axis.ticks.y=element_blank())ExampleConsider the below data frame.> set.seed(321) > x y df dfOutputx y 1 1.0426226 6.238295 2 0.9821990 4.855467 3 0.9930504 6.334253 4 0.9970088 3.552478 5 0.9969010 3.976679 6 1.0067046 5.128251 7 1.0181710 1.853243 8 ...

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How to rotate text in base R plot?

Nizamuddin Siddiqui
Nizamuddin Siddiqui
Updated on 11-Mar-2026 9K+ Views

To write the text in a base R plot, firstly we should create a blank chart by using type="n" if we want to plot only text then the text should be introduced with the help of text function. Now, if we want to rotate the text value then srt argument can be used. For example, if we want to rotate the text to 45 degree then srt = -45 can be used.Example1> plot(1:10, type="n") > text(x=5, y=5, "Text inside plot")OutputExample2> plot(1:10, type="n") > text(x=5, y=5, "Text inside plot", srt=-20)OutputExample3> plot(1:10, type="n") > text(x=5, y=5, "Text inside plot", srt=-45)Output

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How to create horizontal histogram in R?

Nizamuddin Siddiqui
Nizamuddin Siddiqui
Updated on 11-Mar-2026 2K+ Views

Generally, the histogram is a graph that is displayed in vertical form and it helps us to analyze the distribution of a variable, mainly to understand whether the distribution is normal or not. The horizontal histogram can be also created by using coord_flip function of ggplot2 package. Check out the below example to understand how it works.ExampleConsider the below data frame.> x df head(df, 20)Outputx 1 3.509446 2 5.075813 3 5.242884 4 5.236765 5 5.775746 6 5.331167 7 5.250956 8 5.925262 9 6.102322 10 4.045241 11 4.117635 12 4.137581 13 4.758140 14 5.311225 15 4.354592 16 4.021351 17 5.330966 18 ...

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How to create bin frequency table in R?

Nizamuddin Siddiqui
Nizamuddin Siddiqui
Updated on 11-Mar-2026 2K+ Views

The bin frequency table is the table that represent the frequency for a range of values in a particular variable, in R we generally store these variables in a vector or a column of an R data frame. If we want to create a bin frequency table then table function with cut and breaks function can be used.Example1> x1 x1Output[1] 3 4 3 4 3 3 2 5 2 2 4 4 5 4 5 2 5 2 3 2 4 4 3 3 5 2 2 2 2 3 2 4 3 3 3 5 4 [38] 4 3 ...

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How to find the union of two vectors in R?

Nizamuddin Siddiqui
Nizamuddin Siddiqui
Updated on 11-Mar-2026 3K+ Views

The union of vectors return all the unique values in both the vectors. For example, if we have a vector x that contains 1, 2, 3, 4, 2, 3, 4, 1, 1, 4 and another vector that contains 2, 1, 2, 4, 5, 7, 5, 1, 2, 3, 7, 6, 5, 7, 4, 2, 4, 1, 5, 8, 1, 3 then the union of these two vectors will be 1, 2, 3, 4, 5, 6, 7, 8. In R, we can do this by using union function.Example> x1 x1Output[1] 2 2 0 1 1 1 4 1 2 2Example> y1 ...

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Cousins in Binary Tree in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 606 Views

Suppose we have a binary tree, the root node is present at depth 0, and children of each depth k node are at depth k+1.Here two nodes of a binary tree are called cousins if they have the same depth, but have different parents.All values of the tree will be unique, and the values x and y of two different nodes in the tree. We have to check whether the nodes corresponding to the values x and y are cousins or not.So, if the input is likex = 5, y = 4, then the output will be trueTo solve this, ...

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Program to count how many numbers should be appended to create all numbers from 1 to k in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 144 Views

Suppose we have a list of numbers called nums and another value k. We have to find the minimum number of numbers that we need to insert into nums such that we can make any number from [1, k] using some subset in nums.So, if the input is like nums = [3, 5], k = 6, then the output will be 2, as we have to insert 1, 2, so we can make : 1 = [1], 2 = [2], 3 = [3], 4 = [1, 3], 5 = [5], 6 = [1, 5].To solve this, we will follow these ...

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Rotting Oranges in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 289 Views

Suppose we have a grid, here in each cell can have one of three values −value 0 for an empty cell;value 1 for a fresh orange;value 2 for a rotten orange.In every minute, any fresh orange that is adjacent to a rotten orange becomes rotten.We have to find the minimum number of times that must elapse until no cell has a fresh orange. If this is not possible, then return -1.So, if the input is like [[2, 1, 1], [1, 1, 0], [0, 1, 1]], then the output will be 4To solve this, we will follow these steps −minutes := ...

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