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Programming Articles
Page 1230 of 2547
Count Possible Decodings of a given Digit Sequence in C++
We are given a string representing a digit sequence. Each digit is decoded from 1 to 26 as English Alphabet. 1 is ‘A’, 2 is ‘B’ and so on till 26 as ‘Z’. The goal is to find the count of all possible decodings out of a given digit sequence. If the sequence is ‘123’ then possible decodings are ‘ABC’ ( 1-2-3 ), ‘LC’ (12-3), ‘AW’ (1-23). Count is 3.Let us understand with examples.Input − str[]=”1532”Output − Count of Possible Decodings of a given Digit Sequence are − 2Explanation − Possible decodings are AECB - (1-5-3-2) and OCB (15-3-2).Input − ...
Read MoreHow to combine two factor vectors to create one in R?
To combine two factor vectors, we can extract the unique levels of both the vectors then combine those levels. This can be done by using unique function. Also, we can set the levels of the original vectors to the combination of the levels, in this way, we can complete both the vectors with missing levels. Check out the examples below to understand how it works.Example1x1
Read MoreCount the number of rhombi possible inside a rectangle of given size in C++
We are given a rectangle with dimensions as height X width. The rectangle is represented on a 2D coordinate system with the left-lower corner at point (0, 0). So the goal is to count the number of rhombi possible inside this rectangle such that all these conditions are met −The rhombus has an area more than 0.The diagonals of the rhombus are parallel to the x and y axis.The rhombus has integer coordinates for all corners.Let us understand with examplesInput − length=3 width=3Output − Count of number of rhombi possible inside a rectangle of given size are: 4Explanation − Below ...
Read MoreCount positive integers with 0 as a digit and maximum 'd' digits in C++
We are given a number d which represents the number of digits. The goal is to find the count of positive integers with 0 as a digit and have maximum d digits. Count all 1 digit, 2 digit, 3 digit….d digit positive numbers containing at least one 0.We will first find numbers the count of numbers that have d digits with at least one 0. Let’s say d=3. To make a 3-digit number with at least one 0, possible ways are −Here d1 can have 1 to 9 : 9 ways d2 can have 0-9 : 10 ways d3 can ...
Read MoreHow to find minimum value in a numerical vector which is written as a character vector in R?
To find the minimum value of a numeric vector we can directly use min function but if the values are read with double-inverted commas then min function does not work. In this case, we will have to use as.numeric with the vector name so that it can be converted to numeric form before finding the minimum value. For example, if we have a character vector that contains 1, 2, 3, and 4 then the minimum can be found as min(as.numeric(x)).Example1x1
Read MoreHow to repeat a random sample in R?
The random sample can be repeated by using replicate function in R. For example, if we have a vector that contains 1, 2, 3, 4, 5 and we want to repeat this random sample five times then replicate(5, x) can be used and the output will be matrix of the below form:[, 1] [, 2] [, 3] [, 4] [, 5] [1, ] 1 1 1 1 1 [2, ] 2 2 2 2 2 [3, ] 3 3 3 3 3 [4, ] 4 4 4 4 4 [5, ] 5 5 5 5 5Example 1> x1 x1Output[1] 1 ...
Read MoreHow to create a vector with lowercase as well as uppercase letters in R?
To create a vector with lowercase we can use the word letters and for uppercase the word LETTERS is used in R. If we want to create a vector with both type of letters then both of these words can be combined using c function and if want to create a vector with randomly sampled values of lowercase and uppercase letters then sample function can be used.Examples> x1 x1Output[1] "A" "B" "C" "D" "a" "b" "c" "d"Example> x2 x2Output[1] "A" "B" "C" "D" "E" "F" "G" "H" "I" "J" "K" "L" "M" "N" "O" "P" "Q" "R" "S" [20] "T" ...
Read MoreMoving Stones Until Consecutive II in C++
Suppose we are considering an infinite number line, here the position of the i−th stone is given by array stones and stones[i] is indicating ith stone position. A stone is an endpoint stone if it has the smallest or largest position. Now in each turn, we pick up an endpoint stone and move it to an unoccupied position so that it is no longer an endpoint stone.If the stones are at say, stones = [1, 2, 5], we cannot move the endpoint stone at position 5, because moving it to any position (such as 0, or 3) will still keep ...
Read MoreHow to find the cumulative sums by using two factor columns in an R data frame?
Generally, cumulative sums are calculated for a single variable and in some cases based on a single categorical variable, there are very few situations when we want to do it for two categorical variables. If we want to find it for two categorical variables then we need to convert the data frame to a data.table object and use the cumsum function to define the column with cumulative sums.ExampleConsider the below data frame:> set.seed(1361) > Factor1 Factor2 Response df1 df1OutputFactor1 Factor2 Response 1 A T2 9 2 B T1 8 3 B T1 2 4 A T2 3 5 B T1 ...
Read MoreHow to set the legends using ggplot2 on top-right side in R?
The default position of legend in a plot created by using ggplot2 is right hand side but we can change the position by using theme function that has legend.position argument and legend.justification argument. To set the legend on top-right side we can use legend.position="top" and legend.justification="right".ExampleConsider the below data frame:Consider the below data frame:> x freq df dfOutputx freq 1 Mango 212 2 Guava 220 3 Pomegranate 218Loading ggplot2 package and creating bar chart with legend:> library(ggplot2) > ggplot(df, aes(x, freq, fill=x))+geom_bar(stat="identity")Output:Creating the bar chart with legend on top-right hand side of the chart:Example> ggplot(df, aes(x, freq, fill=x))+geom_bar(stat="identity")+theme(legend.position="top", legend.justification="right")Output:
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