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ExampleApproach to solve this problemStep 1 − Define a method that accepts the head of a linked list.Step 2 − If head == nil, return the head.Step 3 − Else, update the last node value to 41.Example Live Demopackage main import "fmt" type Node struct {    value int    next *Node } func NewNode(value int, next *Node) *Node{    var n Node    n.value = value    n.next = next    return &n } func TraverseLinkedList(head *Node){    temp := head    for temp != nil {       fmt.Printf("%d ", temp.value)       temp = temp.next   ... Read More

ExampleApproach to solve this problemStep 1 − Define a method that accepts the head of a linked list.Step 2 − If head == nil, return the head.Step 3 − Else, update the first node value to 29.Example Live Demopackage main import "fmt" type Node struct {    value int    next *Node } func NewNode(value int, next *Node) *Node{    var n Node    n.value = value    n.next = next    return &n } func TraverseLinkedList(head *Node){    temp := head    for temp != nil {       fmt.Printf("%d ", temp.value)       temp = temp.next   ... Read More

ExamplesApproach to solve this problem −Step 1 − Define a method that accepts the head of a linked list.Step 2 − If head == nil, return the head.Step 3 − Go to the next node and return the updated head.Example Live Demopackage main import (    "fmt" ) type Node struct {    value int    next *Node } func NewNode(value int, next *Node) *Node{    var n Node    n.value = value    n.next = next    return &n } func TraverseLinkedList(head *Node){    temp := head    for temp != nil {       fmt.Printf("%d ", temp.value)   ... Read More

ExampleApproach to solve this problemStep 1 − Define a method that accepts the head of a linked list.Step 2 − If head == nil, return the head.Step 3 − Go to the next node and return the updated head.Example Live Demopackage main import "fmt" type Node struct {    value int    next *Node } func NewNode(value int, next *Node) *Node{    var n Node    n.value = value    n.next = next    return &n } func TraverseLinkedList(head *Node){    temp := head    for temp != nil {       fmt.Printf("%d ", temp.value)       temp = ... Read More

ExampleNext5NullApproach to solve this problemStep 1 − Define a method that accepts the head of a linked list.Step 2 − If head == nil, create a new node and return that node.Step 3 − If head is not nil, traverse till the second last of the linked list.Example Live Demopackage main import "fmt" type Node struct {    value int    next *Node } func NewNode(value int, next *Node) *Node{    var n Node    n.value = value    n.next = next    return &n } func TraverseLinkedList(head *Node){    temp := head    for temp != nil {     ... Read More

ExampleApproach to solve this problemStep 1 − Define a method that accepts the head of the linked list.Step 2 − If head == nil, create a new node and return that node.Step 3 − If head is not nil, then update the head of the input linked list.Example Live Demopackage main import "fmt" type Node struct {    value int    next *Node } func NewNode(value int, next *Node) *Node{    var n Node    n.value = value    n.next = next    return &n } func TraverseLinkedList(head *Node){    temp := head    for temp != nil {     ... Read More

ExamplesApproach to solve this problemStep 1 − Define a method that accepts the head of a linked list.Step 2 − If head == nil, return; else, call ReverseLinkedList, recursively.Step 3 − Print head.value at the end.Example Live Demopackage main import "fmt" type Node struct {    value int    next *Node } func NewNode(value int, next *Node) *Node{    var n Node    n.value = value    n.next = next    return &n } func TraverseLinkedList(head *Node){    fmt.Printf("Input Linked List is: ")    temp := head    for temp != nil {       fmt.Printf("%d ", temp.value)     ... Read More

ExamplesApproach to solve this problemStep 1 − Define a method that accepts the head of the linked list.Step 2 − Initialize a variable, count := 0.Step 3 − Iterate the given linked list till it reaches the last node.Step 4 − Increase the count by 1 in the loop.Step 5 − Return count.Example Live Demopackage main import "fmt" type Node struct {    value int    next *Node } func NewNode(value int, next *Node) *Node{    var n Node    n.value = value    n.next = next    return &n } func CountNodes(head *Node){    fmt.Printf("Input Linked List is: ")   ... Read More

ExamplesApproach to solve this problemStep 1 − Let’s define a structure of the node.Step 2 − Make the Linked List such that the previous node would store the address of the next node.Example Live Demopackage main import "fmt" type Node struct {    value int    next *Node } func NewNode(value int) *Node{    var n Node    n.value = value    n.next = nil    return &n } func TraverseLinkedList(head *Node){    fmt.Printf("Linked List: ")    temp := head    for temp != nil {       fmt.Printf("%d ", temp.value)       temp = temp.next    } } ... Read More

ExamplesFor example, n = 1 (Binary Representation of 1: 1)For example, n = 5 (Binary Representation of 5: 101)For example, n = 20 (Binary Representation of 5: 10100)For example, n = 31 (Binary Representation of 31: 11111)Approach to solve this problemStep 1 − Define a method that accepts an integer, n.Step 2 − Convert n into binary representation using golang packageStep 3 − Return the converted binary representation.Example Live Demopackage main import (    "fmt"    "strconv" ) func IntegerToBinary(n int) string {    return strconv.FormatInt(int64(n), 2) } func main(){    n := 1    fmt.Printf("Binary Representation of %d is %s.", ... Read More