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Golang Program to update the last node value in a linked list.
Example
Approach to solve this problem
Step 1 − Define a method that accepts the head of a linked list.
Step 2 − If head == nil, return the head.
Step 3 − Else, update the last node value to 41.
Example
package main import "fmt" type Node struct { value int next *Node } func NewNode(value int, next *Node) *Node{ var n Node n.value = value n.next = next return &n } func TraverseLinkedList(head *Node){ temp := head for temp != nil { fmt.Printf("%d ", temp.value) temp = temp.next } fmt.Println() } func UpdateLastNodeValue(head *Node, data int) *Node{ if head == nil{ return head } temp := head for temp.next != nil{ temp = temp.next } temp.value = data return head } func main(){ head := NewNode(30, NewNode(10, NewNode(40, NewNode(40, nil)))) fmt.Printf("Input Linked list is: ") TraverseLinkedList(head) head = UpdateLastNodeValue(head, 41) fmt.Printf("After updating last node value, linked list is: ") TraverseLinkedList(head) }
Output
Input Linked list is: 30 10 40 40 After updating last node value, linked list is: 30 10 40 41
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