Golang Program to delete the first node from a linked list.


Approach to solve this problem

Step 1 − Define a method that accepts the head of a linked list.

Step 2 − If head == nil, return the head.

Step 3 − Go to the next node and return the updated head.


 Live Demo

package main
import "fmt"
type Node struct {
   value int
   next *Node
func NewNode(value int, next *Node) *Node{
   var n Node
   n.value = value
   n.next = next
   return &n
func TraverseLinkedList(head *Node){
   temp := head
   for temp != nil {
      fmt.Printf("%d ", temp.value)
      temp = temp.next
func DeleteFirstNode(head *Node) *Node{
   if head == nil{
      return head
   newHead := head.next
   head.next = nil
   return newHead
func main(){
   head := NewNode(30, NewNode(10, NewNode(40, NewNode(40, nil))))
   fmt.Printf("Input Linked list is: ")
   head = DeleteFirstNode(head)
   fmt.Printf("After deleting first node of the linked list: ")


Input Linked list is: 30 10 40 40
After deleting first node of the linked list: 10 40 40

Updated on: 18-Mar-2021


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