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Articles on Trending Technologies
Technical articles with clear explanations and examples
How to remove consonants from a string using regular expressions in Java?
The simple character class “[ ]” matches all the specified characters in it. The meta character ^ acts as negation within the above character class i.e. the following expression matches all the characters except b (including spaces and special characters)"[^b]"Similarly, the following expression matches all the consonants in the given input string."([^aeiouyAEIOUY0-9\W]+)";Then you can remove the matched characters by replacing them with the empty string “”, using the replaceAll() method.Example 1public class RemovingConstants { public static void main( String args[] ) { String input = "Hi welc#ome to t$utori$alspoint"; String regex = "([^aeiouAEIOU0-9\W]+)"; ...
Read MoreProgram to match vowels in a string using regular expression in Java
You can group all the required characters to match within the square braces “[ ]” i.e. The metacharacter/sub-expression “[ ]” matches all the specified characters. Therefore, to match all the letters specify the vowel letters within these as shown below −[aeiouAEIOU]Example 1import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class MatchVowels { public static void main( String args[] ) { String regex = "[aeiouAEIOU]"; System.out.println("Enter input string: "); Scanner sc = new Scanner(System.in); String input = sc.nextLine(); //Compiling the regular expression Pattern.compile(regex); ...
Read MoreMoving all Upper case letters to the end of the String using Java RegEx
The subexpression “[ ]” matches all the characters specified in the braces. Therefore, to move all the upper case letters to the end of a string −Iterate through all the characters in the given string.Match all the upper case letters in the given string using the regular expression "[A-Z]".Concatenate the special characters and the remaining characters to two different strings.Finally, concatenate the special characters string to the other string.Example 1public class RemovingSpecialCharacters { public static void main(String args[]) { String input = "sample B text C with G upper case LM characters in between"; ...
Read MoreMoving all special char to the end of the String using Java Regular Expression RegEx)
The following regular expression matches all the special characters i.e. all characters except English alphabet spaces and digits."[^a-zA-Z0-9\s+]"To move all the special characters to the end of the given line, match all the special characters using this regex concatenate them to an empty string and concatenate remaining characters to another string finally, concatenate these two strings.Example 1public class RemovingSpecialCharacters { public static void main(String args[]) { String input = "sample # text * with & special@ characters"; String regex = "[^a-zA-Z0-9\s+]"; String specialChars = ""; String inputData ...
Read MoreC++ Program to calculate the value of sin(x) and cos(x)
Given with the input as angles and the task is to calculate the value of sin(x) and cos(x) corresponding to the given angle and display the resultFor Sin(x)Sin(x) is a trigonometric function which is used to calculate the value of x angle.Formula$$\sin (x) = \displaystyle\sum\limits_{k=0}^\infty \frac{(-1)^{k}}{(2k+1)!}x^{2k+1}$$For Cos(x)Cos(x) is a trigonometric function which is used to calculate the value of x angle.Formula$$\cos (x) = \displaystyle\sum\limits_{k=0}^\infty \frac{(-1)^{k}}{(2k)!}x^{2k}$$Approach used in the below program is as follows −Input the value of x angle for sin(x) and cos(x)Apply the formulas given for sin(x) and cos(x)Print the resultALGORITHMSTART Step 1-> declare function to calculate value of ...
Read MoreC++ Program to compute division upto n decimal places
Given with the value of x and y as a positive integer with the value of n for number of decimal places and the task is to generate the division up to n decimal places.ExampleInput-: x = 36, y = 7, n = 5 Output-: 5.14285 Input-: x = 22, y = 7, n = 10 Output-: 3.1428571428Approach used in the below program is as follows −Input the value of a, b and nCheck if b is 0 than division will go upto infinite and if a is 0 than result will be 0 as something divides to 0 is ...
Read MoreC++ Program to check whether points in a 3-D plane are Coplanar
Given with the points (x1, y1, z1), (x2, y2, z2), (x3, y3, z3) and (x4, y4, z4) and the program must check whether the given points are coplanar or not. Points are said to be coplanar is they lie under same plane and if they are under different-2 planes than the points are not coplanar.Given below is an image containing four points and all are under same plane which is xy plane that means points are coplanarGiven below is an image containing four points and all are under different planes which shows points are not coplanarExampleInput-: x1 = 2, y1 ...
Read MoreC++ Program to check if a given number is Lucky (all digits are different)
Given with a number and the task is to check whether the input number is a lucky number or not and display the result.What is a Lucky NumberLucky number is the number whose each and every digit is different and if at least one digit is repeating than the number will not be considered as a lucky number.ExampleInput-: n = 1234 Output-: it is a lucky number Explanation-: As there is no repeating digit in a number n so it is a lucky number Input-: n = 3434 Output-: it is not a lucky number Explanation-: In the given number ...
Read MoreC++ Program to calculate the number of odd days in given number of years
Given with the positive integer value n and the task is to generate the number of odd days till the given year n.ExampleInput-: days = 500 Output-: number of odd days are: 5 Input-: days = 400 Output-: number of odd days are: 0How to calculate the number of odd days in given number of yearsFor calculating the number of odd days the first thing we need to check is whether the given year is a leap year or not because if it’s a leap year than the number of odd days will get changed. If the year is divisible ...
Read MoreC++ Program to calculate Double Integration
We are given with the lower limit of variable x, upper limit of variable x, lower limit of variable y, upper limit of variable y, steps taken for corresponding x and steps taken for corresponding y and the task is to generate the double integration and display the result.ExampleInput-: steps for x = 1.2 steps for y = 0.54 lower limit of x = 1.3 upper limit of x = 2.1 lower limit of y = 1.0 upper limit for y = 2.1 Output-: double integration is : 2.1Approach used in the below program is as follows −Input the value ...
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