Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
ExamplesFor example, n = 12 => Previous number power of 2 is 8.For example, n = 20 => Previous number power of 2 is 16.Approach to solve this problemStep 1 − Define a method that accepts a number n.Step 2 − Perform n | (n >> k), where k is 1, 2, 4, 8, 16.Step 3 − At the end, return n - (n >> 1).Example Live Demopackage main import "fmt" func PreviousPowOf2(n int) int{ n = n | (n >> 1) n = n | (n >> 2) n = n | (n >> 4) n ... Read More
ExamplesFor example, n = 12 => Next number power of 2 is 16.For example, n = 20 => Next number power of 2 is 32.Approach to solve this problemStep 1 − Define method, that accepts a number n.Step 2 − Iterate k := 1 until k < n.Step 3 − In a loop, calculate k
ExamplesFor example, x = 12, y = 15 => Maximum number is 15.For example, x = 13, y = 17 => Minimum number is 13.Approach to solve this problemStep 1 − Define method, findMax and findMin, that accept two integer x and y.Step 2 − Return integer according to defined method.Example Live Demopackage main import "fmt" func FindMax(x, y int){ fmt.Printf("Maximum element in %d, and %d is: %d", x, y, x - ((x - y) & ((x - y) >> 31))) } func FindMin(x, y int) { fmt.Printf("Minimum element in %d, and %d is: %d", x, y, y ... Read More
ExamplesFor example, 101, 11, 11011 and 1001001 set bits count 2, 2, 4 and 3 respectively.Approach to solve this problemStep 1 − Convert number into binary representation.Step 2 − Count the number of 1s; return count.Example Live Demopackage main import ( "fmt" "strconv" ) func NumOfSetBits(n int) int{ count := 0 for n !=0{ count += n &1 n >>= 1 } return count } func main(){ n := 20 fmt.Printf("Binary representation of %d is: %s.", n, strconv.FormatInt(int64(n), 2)) fmt.Printf("The total number of set bits in %d is %d.", n, NumOfSetBits(n)) }OutputBinary representation of 20 is: 10100. The total number of set bits in 20 is 2.
ExamplesFor example, 101, 11, 11011, 1001001 are Palindrome. 100, 10010 are not Palindrome.Approach to solve this problemStep 1 − Convert number into binary representation.Step 2 − Traverse the converted binary representation from both side and check whether representation is palindrome or not.Example Live Demopackage main import ( "fmt" "strconv" ) func IsPalindrome(n int) bool{ rev := 0 k := n for k != 0 { rev = (rev > 1 } return n == rev } func main(){ n := 3 fmt.Printf("Binary representation of %d is: %s.", n, strconv.FormatInt(int64(n), 2)) if IsPalindrome(n) == true{ fmt.Println("Palindrome") } else { fmt.Println("Not a Palindrome") } }OutputBinary representation of 3 is: 11. Palindrome
ExamplesConsider two numbers m = 65 => 01000001 and n = 80 => 01010000Number of bits flipped is 2.Approach to solve this problemStep 1 − Convert both numbers into bits.Step 2 − Count number of bits are flipped.Example Live Demopackage main import ( "fmt" "strconv" ) func FindBits(x, y int) int{ n := x ^ y count := 0 for ;n!=0; count++{ n = n & (n-1) } return count } func main(){ x := 65 y := 80 fmt.Printf("Binary of %d is: %s.", x, strconv.FormatInt(int64(x), 2)) ... Read More
Definition − Parity refers to the count of 1s. If count of 1s is even, then it’s even parity; and if the count of 1s is odd, then the parity is Odd.ExamplesConsider n = 20(00010100)Parity of the given number 20 is even.Approach to solve this problemStep 1 − Define a method, where n and is an argument, return type is int.Step 2 − Calculate the count of 1s in the given number’s bit.Example Live Demopackage main import ( "fmt" "strconv" ) func FindParity(n int) bool { parity := false for n != 0 { ... Read More
ExamplesConsider n = 20(00010100)Now return log2(20 & -20) => 2+1 => 3Approach to solve this problemStep 1 − Define a method, where n and is an argument, return type is int.Step 2 − Return log2(n & -n)+1.Examplepackage main import ( "fmt" "math" "strconv" ) func FindRightMostSetBit(n int) int { if (n & 1) != 0{ return 1 } return int(math.Log2(float64(n & -n))) + 1 } func main(){ var n = 20 fmt.Printf("Binary of %d is: %s.", n, strconv.FormatInt(int64(n), 2)) fmt.Printf("Position of the rightmost set bit of the given number %d is %d.", n, FindRightMostSetBit(n)) }OutputBinary of 20 is: 10100. Position of the rightmost set bit of the given number 20 is 3.
ExamplesConsider n = 16(00010000)Now find x = n-1 => 15(00001111) => x & n => 0Approach to solve this problemStep 1 − Define a method, where n and is an argument, returns type is int.Step 2 − Perform x = n & n-1.Step 3 − If x is 0, then the given number is power of 2; else not.Example Live Demopackage main import ( "fmt" "strconv" ) func CheckNumberPowerOfTwo(n int) int { return n & (n-1) } func main(){ var n = 16 fmt.Printf("Binary of %d is: %s.", n, strconv.FormatInt(int64(n), 2)) flag := CheckNumberPowerOfTwo(n) ... Read More
ExamplesConsider n = 20(00010100), k = 3.After toggling the kth bit of the given number: 00010000 => 16.Approach to solve this problemStep 1 − Define a method, where n and k would be the arguments, returns type is int.Step 2 − Perform AND operation with n ^ (1