- Add and Subtract Fractions
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- Add or Subtract Fractions With the Same Denominator
- Add or Subtract Fractions With the Same Denominator and Simplification
- Finding the LCD of Two Fractions
- Addition or Subtraction of Unit Fractions
- Addition or Subtraction of Fractions With Different Denominators
- Add or Subtract Fractions With Different Denominators Advanced
- Word Problem Involving Add or Subtract Fractions With Different Denominators
- Fractional Part of a Circle
Addition or Subtraction of Unit Fractions Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Addition or Subtraction of Unit Fractions. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : D
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.
LCD is 4 × 7 = 28.
Step 2:
Rewriting as equivalent fractions
$\frac{7}{28}$ + $\frac{4}{28}$ = $\frac{(7+4)}{28}$ = $\frac{11}{28}$
Step 3:
So, $\frac{1}{4}$ + $\frac{1}{7}$ = $\frac{11}{28}$
Answer : A
Explanation
Step 1:
Since denominators are same, subtracting the numerators
Here the fractions have unlike denominators. So we find LCD.
LCD = 7 × 10 = 70.
Step 2:
Rewriting as equivalent fractions
$\frac{10}{70}$ − $\frac{7}{70}$ = $\frac{(10-7)}{70}$ = $\frac{3}{70}$
Step 3:
So, $\frac{1}{7}$ − $\frac{1}{10}$ = $\frac{3}{70}$
Answer : C
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.
LCD = 2 × 9 = 18.
Step 2:
Rewriting as equivalent fractions
$\frac{9}{18}$ + $\frac{2}{18}$ = $\frac{(9+2)}{18}$ = $\frac{11}{18}$
Step 3:
So, $\frac{1}{2}$ + $\frac{1}{9}$ = $\frac{11}{18}$
Answer : B
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.
LCD = 9 × 10 = 90.
Step 2:
Rewriting as equivalent fractions
$\frac{10}{90}$ − $\frac{9}{90}$ = $\frac{(10-9)}{90}$ = $\frac{1}{90}$
Step 3:
So, $\frac{1}{9}$ − $\frac{1}{10}$ = $\frac{1}{90}$
Answer : A
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.
LCD is 3 × 7 = 21.
Step 2:
Rewriting as equivalent fractions
$\frac{7}{21}$ + $\frac{3}{21}$ = $\frac{(7+3)}{21}$ = $\frac{10}{21}$
Step 3:
So, $\frac{1}{3}$ + $\frac{1}{7}$ = $\frac{10}{21}$
Answer : C
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.
LCD is 9 × 11 = 99.
Step 2:
Rewriting as equivalent fractions
$\frac{11}{99}$ − $\frac{9}{99}$ = $\frac{(11-9)}{99}$ = $\frac{2}{99}$
Step 3:
So, $\frac{1}{9}$ - $\frac{1}{11}$ = $\frac{2}{99}$
Answer : D
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.
LCD of 3 and 6 is 6.
Step 2:
Rewriting as equivalent fractions
$\frac{2}{6}$ + $\frac{1}{6}$ = $\frac{(2+1)}{6}$ = $\frac{3}{6}$ = $\frac{1}{2}$
Step 3:
So, $\frac{1}{3}$ + $\frac{1}{6}$ = $\frac{1}{2}$
Answer : B
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.
LCD of 6 and 8 = 24.
Step 2:
Rewriting as equivalent fractions
$\frac{4}{24}$ − $\frac{3}{24}$ = $\frac{(4-3)}{24}$ = $\frac{1}{24}$
Step 3:
So, $\frac{1}{6}$ − $\frac{1}{8}$ = $\frac{1}{24}$
Answer : C
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.
LCD is 2 × 5 = 10.
Step 2:
Rewriting as equivalent fractions
$\frac{5}{10}$ + $\frac{2}{10}$ = $\frac{(5+2)}{10}$ = $\frac{7}{10}$
Step 3:
So, $\frac{1}{2}$ + $\frac{1}{5}$ = $\frac{7}{10}$
Answer : A
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.
LCD is 8 × 9 = 72.
Step 2:
Rewriting as equivalent fractions
$\frac{9}{72}$ − $\frac{8}{72}$ = $\frac{(9-8)}{72}$ = $\frac{1}{72}$
Step 3:
So, $\frac{1}{8}$ − $\frac{1}{9}$ = $\frac{1}{72}$
