- Add and Subtract Fractions
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- Add or Subtract Fractions With the Same Denominator
- Add or Subtract Fractions With the Same Denominator and Simplification
- Finding the LCD of Two Fractions
- Addition or Subtraction of Unit Fractions
- Addition or Subtraction of Fractions With Different Denominators
- Add or Subtract Fractions With Different Denominators Advanced
- Word Problem Involving Add or Subtract Fractions With Different Denominators
- Fractional Part of a Circle
Addition or Subtraction of Fractions With Different Denominators Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Addition or Subtraction of Fractions With Different Denominators. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Answer : B
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD. LCD is 3 × 5 = 15.
Step 2:
Rewriting as equivalent fractions and adding
$\frac{5}{15}$ + $\frac{12}{15}$ = $\frac{5+12}{15}$ = $\frac{17}{15}$
Step 3:
So, $\frac{1}{3}$ + $\frac{4}{5}$ = $\frac{17}{15}$
Answer : C
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD. LCD is 13 × 11 = 143.
Step 2:
Rewriting as equivalent fractions and subtracting
$\frac{22}{143}$ − $\frac{13}{143}$ = $\frac{(22-13)}{143}$ = $\frac{9}{143}$
Step 3:
So, $\frac{2}{13}$ − $\frac{1}{11}$ = $\frac{9}{143}$
Answer : A
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.LCD is 9 × 8 = 72.
Step 2:
Rewriting as equivalent fractions and adding
$\frac{8}{72}$ + $\frac{27}{72}$ = $\frac{(8+27)}{72}$ = $\frac{35}{72}$
Step 3:
So, $\frac{1}{9}$ + $\frac{3}{8}$ = $\frac{35}{72}$
Answer : D
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD. LCD is 36.
Step 2:
Rewriting as equivalent fractions and subtracting
$\frac{9}{36}$ − $\frac{4}{36}$ = $\frac{(9-4)}{36}$ = $\frac{5}{36}$
Step 3:
So, $\frac{3}{12}$ − $\frac{1}{9}$ = $\frac{5}{36}$
Answer : C
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.LCD is 4 × 7 = 28.
Step 2:
Rewriting as equivalent fractions and adding
$\frac{7}{28}$ + $\frac{12}{28}$ = $\frac{(7+12)}{28}$ = $\frac{19}{28}$
Step 3:
So, $\frac{1}{4}$ + $\frac{3}{7}$ = $\frac{19}{28}$
Answer : D
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD. LCD is 11 × 10 = 110.
Step 2:
Rewriting as equivalent fractions and subtracting
$\frac{30}{110}$ − $\frac{11}{110}$ = $\frac{30-11}{110}$ = $\frac{19}{110}$
Step 3:
So, $\frac{3}{11}$ - $\frac{1}{10}$ = $\frac{19}{110}$
Answer : A
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.LCD is 6 × 7 = 42.
Step 2:
Rewriting as equivalent fractions and adding
$\frac{7}{42}$ + $\frac{30}{42}$ = $\frac{7+30}{42}$ = $\frac{37}{42}$
Step 3:
So, $\frac{1}{6}$ + $\frac{5}{7}$ = $\frac{37}{42}$
Answer : B
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD. LCD 13 × 12 = 156.
Step 2:
Rewriting as equivalent fractions and subtracting
$\frac{36}{156}$ − $\frac{13}{156}$ = $\frac{(36-13)}{156}$ = $\frac{23}{156}$
Step 3:
So, $\frac{3}{13}$ − $\frac{1}{12}$ = $\frac{23}{156}$
Answer : C
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD. LCD is 15 as 15 is multiple of 5.
Step 2:
Rewriting as equivalent fractions and subtracting
$\frac{4}{15}$ − $\frac{3}{15}$ = $\frac{(4-3)}{15}$ = $\frac{1}{15}$
Step 3:
So, $\frac{4}{15}$ - $\frac{1}{5}$ = $\frac{1}{15}$
Answer : D
Explanation
Step 1:
Here the fractions have unlike denominators. So we find LCD.LCD is 3 × 5 = 15.
Step 2:
Rewriting as equivalent fractions and adding
$\frac{3}{15}$ + $\frac{10}{15}$ = $\frac{(3+10)}{15}$ = $\frac{13}{15}$
Step 3:
So, $\frac{1}{5}$ + $\frac{2}{3}$ = $\frac{13}{15}$
