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Addition or Subtraction of Fractions With Different Denominators Online Quiz

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Following quiz provides Multiple Choice Questions (MCQs) related to Addition or Subtraction of Fractions With Different Denominators. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Answer : B

Explanation

Step 1:

Here the fractions have unlike denominators. So we find LCD. LCD is 3 × 5 = 15.

Step 2:

Rewriting as equivalent fractions and adding

$\frac{5}{15}$ + $\frac{12}{15}$ = $\frac{5+12}{15}$ = $\frac{17}{15}$

Step 3:

So, $\frac{1}{3}$ + $\frac{4}{5}$ = $\frac{17}{15}$

Q 2 - Subtract $\frac{2}{13}$ − $\frac{1}{11}$

Answer : C

Explanation

Step 1:

Here the fractions have unlike denominators. So we find LCD. LCD is 13 × 11 = 143.

Step 2:

Rewriting as equivalent fractions and subtracting

$\frac{22}{143}$ − $\frac{13}{143}$ = $\frac{(22-13)}{143}$ = $\frac{9}{143}$

Step 3:

So, $\frac{2}{13}$ − $\frac{1}{11}$ = $\frac{9}{143}$

Answer : A

Explanation

Step 1:

Here the fractions have unlike denominators. So we find LCD.LCD is 9 × 8 = 72.

Step 2:

Rewriting as equivalent fractions and adding

$\frac{8}{72}$ + $\frac{27}{72}$ = $\frac{(8+27)}{72}$ = $\frac{35}{72}$

Step 3:

So, $\frac{1}{9}$ + $\frac{3}{8}$ = $\frac{35}{72}$

Q 4 - Subtract $\frac{3}{12}$ − $\frac{1}{9}$

Answer : D

Explanation

Step 1:

Here the fractions have unlike denominators. So we find LCD. LCD is 36.

Step 2:

Rewriting as equivalent fractions and subtracting

$\frac{9}{36}$ − $\frac{4}{36}$ = $\frac{(9-4)}{36}$ = $\frac{5}{36}$

Step 3:

So, $\frac{3}{12}$ − $\frac{1}{9}$ = $\frac{5}{36}$

Answer : C

Explanation

Step 1:

Here the fractions have unlike denominators. So we find LCD.LCD is 4 × 7 = 28.

Step 2:

Rewriting as equivalent fractions and adding

$\frac{7}{28}$ + $\frac{12}{28}$ = $\frac{(7+12)}{28}$ = $\frac{19}{28}$

Step 3:

So, $\frac{1}{4}$ + $\frac{3}{7}$ = $\frac{19}{28}$

Answer : D

Explanation

Step 1:

Here the fractions have unlike denominators. So we find LCD. LCD is 11 × 10 = 110.

Step 2:

Rewriting as equivalent fractions and subtracting

$\frac{30}{110}$ − $\frac{11}{110}$ = $\frac{30-11}{110}$ = $\frac{19}{110}$

Step 3:

So, $\frac{3}{11}$ - $\frac{1}{10}$ = $\frac{19}{110}$

Answer : A

Explanation

Step 1:

Here the fractions have unlike denominators. So we find LCD.LCD is 6 × 7 = 42.

Step 2:

Rewriting as equivalent fractions and adding

$\frac{7}{42}$ + $\frac{30}{42}$ = $\frac{7+30}{42}$ = $\frac{37}{42}$

Step 3:

So, $\frac{1}{6}$ + $\frac{5}{7}$ = $\frac{37}{42}$

Q 8 - Subtract $\frac{3}{13}$ − $\frac{1}{12}$

Answer : B

Explanation

Step 1:

Here the fractions have unlike denominators. So we find LCD. LCD 13 × 12 = 156.

Step 2:

Rewriting as equivalent fractions and subtracting

$\frac{36}{156}$ − $\frac{13}{156}$ = $\frac{(36-13)}{156}$ = $\frac{23}{156}$

Step 3:

So, $\frac{3}{13}$ − $\frac{1}{12}$ = $\frac{23}{156}$

Q 9 - Subtract $\frac{4}{15}$ - $\frac{1}{5}$

Answer : C

Explanation

Step 1:

Here the fractions have unlike denominators. So we find LCD. LCD is 15 as 15 is multiple of 5.

Step 2:

Rewriting as equivalent fractions and subtracting

$\frac{4}{15}$ − $\frac{3}{15}$ = $\frac{(4-3)}{15}$ = $\frac{1}{15}$

Step 3:

So, $\frac{4}{15}$ - $\frac{1}{5}$ = $\frac{1}{15}$

Answer : D

Explanation

Step 1:

Here the fractions have unlike denominators. So we find LCD.LCD is 3 × 5 = 15.

Step 2:

Rewriting as equivalent fractions and adding

$\frac{3}{15}$ + $\frac{10}{15}$ = $\frac{(3+10)}{15}$ = $\frac{13}{15}$

Step 3:

So, $\frac{1}{5}$ + $\frac{2}{3}$ = $\frac{13}{15}$

addition_or_subtraction_of_fractions_with_different_denominators.htm
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