When we have addition or subtraction of fractions with unlike denominators, we first find the Least Common Denominator (LCD) of the fractions. We then rewrite all fractions as equivalent fractions with LCD as the denominator. Now that all denominators are alike, we add or subtract the numerators and put the result over the common denominator to get the answer. If necessary, we express the fraction in lowest terms.

Add $\frac{3}{5}$ + $\frac{3}{8}$

Solution

Step 1:

Add $\frac{3}{5}$ + $\frac{3}{8}$

Here the denominators are different. The LCD is 40 (product of 5 and 8) as 5 and 8 are co-prime numbers.

Step 2:

Rewriting

$\frac{3}{5}$ + $\frac{3}{8}$ = $\frac{(3×8)}{(5×8)}$ + $\frac{(5×5)}{(8×5)}$ = $\frac{24}{40}$ + $\frac{25}{40}$

As the denominators have become equal

$\frac{24}{40}$ + $\frac{25}{40}$ = $\frac{(24+25)}{40}$ = $\frac{49}{40}$

Step 3:

So, $\frac{3}{5}$ + $\frac{3}{8}$ = $\frac{49}{40}$

Subtract $\frac{5}{8}$$\frac{7}{12} Solution Step 1: \frac{5}{8}$$\frac{7}{12}$

Here the denominators are different. The LCD here is 24.

Step 2:

Rewriting

$\frac{5}{8}$$\frac{7}{12} = \frac{(5×3)}{(8×3)}$$\frac{(7×2)}{(12×2)}$ = $\frac{15}{24}$$\frac{14}{24} As the denominators have become equal \frac{15}{24}$$\frac{14}{24}$ = $\frac{(15−14)}{24}$ = $\frac{1}{24}$

Step 3:

So, $\frac{5}{8}$$\frac{7}{12}$ = $\frac{1}{24}$