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8085 program to add three 16 bit numbers stored in registers
In this program we will see how to add three 16-bit numbers stored in register pairs.
Problem Statement
Write 8085 Assembly language program to add three 16-bit numbers stored in register pair BC, DE and HL. Store the result at DE register pair.
Discussion
In this program we are storing the 16-bit numbers into BC, DE and HL pair. We have DAD D instruction which helps to add HL and DE register pair, and store the result into HL pair. After that copy BC to DE, then again perform DAD D to add them. Finally using XCHG we are storing them into DE register pair.
Here we are adding 0502H + 1211H + 2133H = 3846H
Input
| Register | Data |
|---|---|
| BC | 0502 |
| DE | 1211 |
| HL | 2133 |
Flow Diagram
Program
| Address | HEX Codes | Labels | Mnemonics | Comments |
|---|---|---|---|---|
| F000 | 01, 02, 05 | | LXI B,0502H | |
| F003 | 11, 11, 12 | | LXI D,1211H | |
| F006 | 21, 33, 21 | | LXI H,2133H | |
| F009 | 19 | | DAD D | Add DE and HL, and Store into HL |
| F00A | 50 | | MOV D,B | Copy B to D |
| F00B | 59 | | MOV E,C | Copy C to E |
| F00C | 19 | | DAD D | Add DE and HL (Actually BC), store into HL |
| F00D | EB | | XCHG | Swap DE and HL |
| F00E | 76 | | HLT | terminate the program |
Output
| Register | Data |
|---|---|
DE | 3846 |
Updated on: 30-Jul-2019
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