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Program to Add two 8 Bit numbers in 8085 Microprocessor
Here we will see one 8085 assembly language program. In this program we will see how to add two 8-bit numbers.
Problem Statement −
Write an 8085 Assembly language program to add two 8-bit numbers and store the result at locations 8050H and 8051H.
Discussion −
To perform this task, we are using the ADD operation of 8085 Microprocessor. When the result of addition is 1-byte result, then the carry flag will not be enabled. When the result is exceeding the 1-byte range, then the carry flag will be 1
We are using two numbers at location 8000H and 8001H. When the numbers are 6CH and 24H, then the result will be (6C + 24 = 90) and when the numbers are FCH and 2FH, then the result will be (FC + 2F = 12B) Here the result is exceeding the range of 1-byte.
Input
first input
| Address | Data |
|---|---|
| … | … |
| 8000 | 6C |
| 8001 | 24 |
| … | … |
second input
| Address | Data |
|---|---|
| … | … |
| 8000 | FC |
| 8001 | 2F |
| … | … |
Flow Diagram
Program
| Address | HEX Codes | Labels | Mnemonics | Comments |
|---|---|---|---|---|
| F000 | 0E, 00 | MVI C,00H | Clear C register | |
| F002 | 21, 00, 80 | LXI H,8000H | Load initial address to get operand | |
| F005 | 7E | MOV A,M | Load Acc with memory element | |
| F006 | 23 | INX H | Point to next location | |
| F007 | 46 | MOV B,M | Load B with second operand | |
| F008 | 80 | SUB B | Add B with A | |
| F009 | D2, 0D, F0 | JNC STORE | When CY = 0, go to STORE | |
| F00C | 0C | INR C | Increase C by 1 | |
| F00D | 21, 50, 80 | STORE | LXI H,8050H | Load the destination address |
| F010 | 77 | MOV M,A | Store the result | |
| F011 | 23 | INX H | Point to next location | |
| F012 | 71 | MOV M,C | Store the carry | |
| F013 | 76 | HLT | Terminate the program |
Output
first output
| Address | Data |
|---|---|
| … | … |
| 8050 | 90 |
| 8051 | 00 |
| … | … |
second output
| Address | Data |
|---|---|
| … | … |
| 8050 | 2B |
| 8051 | 01 |
| … | … |
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