Java Examples - Multiple Exceptions (Array out of bound)


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Problem Description

How to handle multiple exceptions while array is out of bound ?

Solution

This example shows how to handle multiple exception methods by using System.err.println() method of System class.

public class Main {
   public static void main (String args[]) {
      int array[] = {20,20,40};
      int num1 = 15, num2 = 10;
      int result = 10;
      try {
         result = num1/num2;
         System.out.println("The result is" +result);
         for(int i = 5; i >=0; i--) {
            System.out.println("The value of array is" +array[i]);
         }
      } catch (ArrayIndexOutOfBoundsException e) {
         System.out.println("Array is out of Bounds"+e);
      } catch (ArithmeticException e) {
         System.out.println ("Can't divide by Zero"+e);
      }
   }
}

Result

The above code sample will produce the following result.

The result is1
Array is out of Boundsjava.lang.ArrayIndexOutOfBoundsException : 5

java_exceptions.htm

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