Number cards are arranged with numbers in ascending order. The difference between any two consecutive cards is the same. Which of the following best replaces the question mark?$\frac{1}{5}$ ? $\frac{1}{4}$
Given :
Number cards are arranged with numbers in ascending order.
The first number card is $\frac{1}{5}$
The fourth number card is $\frac{1}{4}$
To find :
We have to find the number which replaces the question mark
Solution :
Let the difference between any two number cards be x.
Therefore,
$\frac{1}{4} =3x+\frac{1}{5}$
$3x=\frac{1}{4} -\frac{1}{5}$
$3x=\frac{1\times 5-1\times 4}{20}$ [ LCM of 4 and 5 is 20]
$3x=\frac{5-4}{20}$
$3x=\frac{1}{20}$
$x=\frac{1}{3\times 20}$
$x=\frac{1}{60}$
Therefore,
The third number card( ?) $ =2x+\frac{1}{5}$
$=2\left(\frac{1}{60}\right) +\frac{1}{5}$
$ =\frac{1}{30} +\frac{1}{5}$
$ =\frac{1\times 1+1\times 6}{30} $ [ LCM of 30 and 5 is 30]
$ =\frac{1+6}{30}$
$=\frac{7}{30}$
The number is $\frac{7}{30}$
Related Articles Write the following in ascending order:$\frac{1}{2},\ \frac{4}{5},\ \frac{-2}{3},\ \frac{-1}{2},\ \frac{-5}{7}$.
Arrange the following in ascending order$ \frac{5}{8}, \frac{5}{6}, \frac{1}{2} $
Write the following rational numbers in ascending order:$(i)$. $\frac{-3}{5},\ \frac{-2}{5},\ \frac{-1}{5}$$(ii)$. $\frac{1}{3},\ \frac{-2}{9},\ \frac{-4}{3}$$(iii)$. $\frac{-3}{7},\ \frac{-3}{2},\ \frac{-3}{4}$
Which of the following is greater?$\frac{1}{4} \times \frac{1}{4}$ or $\frac{1}{4} \times \frac{1}{7}$
Write the following fractions in ascending order.$\frac{4}{7}, \frac{7}{5}, \frac{2}{5}, \frac{5}{9}$.
Simpify the following :$(\frac{16}{17} of 6 \frac{4}{5}) -4 \frac{1}{5}-[1 \frac{1}{14} \div(\frac{1}{2}+\frac{1}{7})] $
Which of the following is greater?$\frac{-1}{5}$ or $\frac{-1}{2}$
Name the property under multiplication used in each of the following:\( \frac{-4}{5} \times 1=1 \times \frac{-4}{5}=-\frac{4}{5} \)
The difference of two natural number is 5 and the difference of their reciprocals is $\frac {1}{10}$. Find the numbers.
Name the property used in the following:$[\frac{2}{3}+(\frac{-4}{5})]+\frac{1}{6}=\frac{2}{3}+[(\frac{-4}{5})+\frac{1}{6}]$
The angles of a triangle are arranged in ascending order of magnitude. If the difference between two consecutive angle is $10^o$, find the three angles.
Arrange the given rational number in ascending order.\( \frac{4}{-9}, \frac{-5}{12} \) and \( \frac{2}{-3} \)
Solve the following:$3 \frac{2}{5} \div \frac{4}{5} of \frac{1}{5} + \frac{2}{3} of \frac{3}{4} - 1 \frac{35}{72}$.
Find two rational numbers between $\frac{1}{5}$ and $\frac{1}{2}$.
Solve the following:$4\frac{1}{6}\times\frac{2}{5}\div\frac{1}{3}$
Kickstart Your Career
Get certified by completing the course
Get Started