Solve the following:$4\frac{1}{6}\times\frac{2}{5}\div\frac{1}{3}$

Given:  $4\frac{1}{6}\times\frac{2}{5}\div\frac{1}{3}$

To do: Solve the expression

Solution: 

Convert the mixed fraction to improper fraction:

So, $4\frac{1}{6}=\frac{25}{6}$  

Now, $\frac{25}{6}\times\frac{2}{5}\div\frac{1}{3}$

$\frac{25}{6}\times\frac{2}{5}\times3$

$\frac{25\times2\times3}{6\times5}$

$\frac{5\times2}{2}$                           [$5\times5=25 and 3\times2=6$]

Therefore the solution is $5$

$4\frac{1}{6}=\frac{4\times 6+1}{6}=\frac{25}{6}\mathrm{.}$

$$$4\frac{1}{6} \ =\ \frac{4\times 6\ +\ 1}{6} \ =\ \frac{25}{6}.$

$\ 4\frac{1}{6} \ =\ \frac{4\times Now,6\ +\ 1}{6}$