Return the inner product of two masked arrays with different shapes in Numpy

NumpyServer Side ProgrammingProgramming

To return the inner product of two masked arrays with different shapes, use the ma.inner() method in Python Numpy.

Ordinary inner product of vectors for 1-D arrays (without complex conjugation), in higher dimensions a sum product over the last axes.

The out parameter suggests, if both the arrays are scalars or both 1-D arrays then a scalar is returned; otherwise an array is returned. out.shape = (*a.shape[:-1], *b.shape[:-1]).

A masked array is the combination of a standard numpy.ndarray and a mask. A mask is either nomask, indicating that no value of the associated array is invalid, or an array of booleans that determines for each element of the associated array whether the value is valid or not.

Steps

At first, import the required library −

import numpy as np

Create Array 1, a 3D array with int elements using the numpy.arange() method −

arr1 = np.arange(4).reshape((1, 2, 2))
print("Array1...\n", arr1)
print("\nArray type...\n", arr1.dtype)

Create a masked array −

arr1 = ma.array(arr1)

Mask Array1 −

arr1[0, 0, 1] = ma.masked

Display Masked Array 1 −

print("\nMasked Array1...\n",arr1)

Create Array 2, a 2D array with int elements using the numpy.arange() method −

arr2 = np.arange(6).reshape((3,2))
print("\nArray2...\n", arr2)
print("\nArray type...\n", arr2.dtype)

Create a masked array −

arr2 = ma.array(arr2)

Mask Array2 −

arr2[0, 1] = ma.masked

Display Masked Array 2 −

print("\nMasked Array2...\n",arr2)

To return the inner product of two masked arrays with different shapes, use the ma.inner() method −

print("\nResult of inner product...\n",np.ma.inner(arr1, arr2))

Example

import numpy as np

# Array 1
# Creating a 3D array with int elements using the numpy.arange() method
arr1 = np.arange(4).reshape((1, 2, 2))
print("Array1...\n", arr1)
print("\nArray type...\n", arr1.dtype)

# Get the dimensions of the Array
print("\nArray Dimensions...\n",arr1.ndim)

# Get the shape of the Array
print("\nOur Array Shape...\n",arr1.shape)

# Get the number of elements of the Array
print("\nElements in the Array...\n",arr1.size)

# Create a masked array arr1 = ma.array(arr1)

# Mask Array1 arr1[0, 0, 1] = ma.masked

# Display Masked Array 1
print("\nMasked Array1...\n",arr1)

# Array 2
# Creating a 2D array with int elements using the numpy.arange() method
arr2 = np.arange(6).reshape((3,2))
print("\nArray2...\n", arr2)
print("\nArray type...\n", arr2.dtype)

# Get the dimensions of the Array
print("\nArray Dimensions...\n",arr2.ndim)

# Get the shape of the Array
print("\nOur Array Shape...\n",arr2.shape)

# Get the number of elements of the Array
print("\nElements in the Array...\n",arr2.size)

# Create a masked array arr2 = ma.array(arr2)

# Mask Array2 arr2[0, 1] = ma.masked

# Display Masked Array 2
print("\nMasked Array2...\n",arr2)

# To return the inner product of two masked arrays with different shapes, use the ma.inner() method in Python Numpy
print("\nResult of inner product...\n",np.ma.inner(arr1, arr2))

Output

Array1...
[[[0 1]
[2 3]]]

Array type...
int64

Array Dimensions...
3

Our Array Shape...
(1, 2, 2)

Elements in the Array...
4

Masked Array1...
[[[0 1]
[2 3]]]

Array2...
[[0 1]
[2 3]
[4 5]]

Array type...
int64

Array Dimensions...
2

Our Array Shape...
(3, 2)

Elements in the Array...
6

Masked Array2...
[[0 1]
[2 3]
[4 5]]

Result of inner product...
[[[ 1 3 5]
[ 3 13 23]]]
raja
Updated on 05-Feb-2022 11:48:04

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