
- Ratios and Unit Rates
- Home
- Writing Ratios Using Different Notations
- Writing Ratios for Real-World Situations
- Identifying Statements that Describe a Ratio
- Simplifying a Ratio of Whole Numbers: Problem Type 1
- Simplifying a Ratio of Decimals
- Finding a Unit Price
- Using Tables to Compare Ratios
- Computing Unit Prices to Find the Better Buy
- Word Problem on Unit Rates Associated with Ratios of Whole Numbers: Decimal Answers
- Solving a Word Problem on Proportions Using a Unit Rate
- Solving a One-Step Word Problem Using the Formula d = rt
- Function Tables with One-Step Rules
- Finding Missing Values in a Table of Equivalent Ratios
- Using a Table of Equivalent Ratios to Find a Missing Quantity in a Ratio
- Writing an Equation to Represent a Proportional Relationship
Finding Missing Values in a Table of Equivalent Ratios
You can find equivalent ratios by multiplying or dividing both terms of a ratio by the same number. This is similar to finding equivalent fractions of a given fraction. All the ratios in the tables below are equivalent.
The table below represent the equivalent ratios 1:3, 2:6, 3:9
1 | 3 |
2 | 6 |
3 | 9 |
The table below represent the equivalent ratios 1:4, 3:12, 5:20
1 | 4 |
3 | 12 |
5 | 20 |
Such tables of equivalent ratios can be used to find missing values as follows.
Find the missing values in the following table of equivalent ratios:
3 | 10 |
6 | x |
9 | 30 |
y | 40 |
Solution
Step 1:
Find the missing values in the following table of equivalent ratios :
$\frac{x}{6} = \frac{10}{3}; x = \frac{10}{3} \times 6 = \frac{10}{3} \times \frac{6}{1} = 20$
$\frac{y}{40} = \frac{3}{10}; y = \frac{3}{10} \times 40 = \frac{3}{10} \times \frac{40}{1} = 12$
Step 2:
So, $x = 9; y = 28$
Find the missing values in the following table of equivalent ratios:
2 | 3 |
4 | 6 |
6 | x |
y | 12 |
Solution
Step 1:
Since the table gives values of equivalent ratios
$\frac{x}{6} = \frac{3}{2}; x = \frac{3}{2} \times \frac{6}{1} = \frac{3}{2} \times \frac{6}{1} = 9$
$\frac{y}{12} = \frac{2}{3}; y = \frac{2}{3} \times 12 = \frac{2}{3} \times \frac{12}{1} = 8$
Step 2:
So, $x = 9; y = 8$