Python Program to solve Maximum Subarray Problem using Kadane’s Algorithm

When it is required to find the maximum sub array using Kadane’s algorithm, a method is defined that helps find the maximum of the sub array. Iterators are used to keep track of the maximum sub array.

Below is the demonstration of the same −


 Live Demo

def find_max_sub_array(my_list, beg, end):
   max_end_at_i = max_seen_till_now = my_list[beg]
   max_left_at_i = max_left_till_now = beg
   max_right_till_now = beg + 1
   for i in range(beg + 1, end):
      if max_end_at_i > 0:
         max_end_at_i += my_list[i]
         max_end_at_i = my_list[i]
         max_left_at_i = i
      if max_end_at_i > max_seen_till_now:
         max_seen_till_now = max_end_at_i
         max_left_till_now = max_left_at_i
         max_right_till_now = i + 1
   return max_left_till_now, max_right_till_now, max_seen_till_now

my_list = input('Enter the list of numbers... ')
my_list = my_list.split()
my_list = [int(x) for x in my_list]
beg, end, max_val = find_max_sub_array(my_list, 0, len(my_list))
print('The maximum subarray begins at index {}, ends at index {}'
   ' and its sum is {}.'.format(beg, end - 1, max_val))


Enter the list of numbers... 2 5 7 12 6 8
The maximum subarray begins at index 0, ends at index 5 and its sum is 40.


  • A method named ‘find_max_sub_array’ is defined that takes three parameters.

  • The maximum sub array within a given range is found.

  • It returns a tuple where the left, right indices of the maximum sub array are returned along with its sum.

  • A loop is used to keep a check on the maximum sub array that ends at index i.

  • This is the maximum of all sub arrays.

  • The method also keeps track of maximum sum of the sub array seen until now, as the loop iterates through the left and right indices.

  • Outside the method, the list of numbers is taken as input by the user.

  • This is passed as a parameter to the method.

  • It is displayed as output on the console.