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Maximum Subarray in Python
Suppose we have an integer array A. We have to find the contiguous subarrays which length will be at least one, and that has the largest sum, and also return its sum. So if the array A is like A = [-2,1,-3,4,-1,2,1,-5,4], then the sum will be 6. And the subarray will be [4, -1, 2, 1]
To solve this we will try to use the Dynamic programming approach.
- define an array dp same as the size of A, and fill it with 0
- dp[0] := A[0]
- for i = 1 to the size of A – 1
- dp[i] := maximum of dp[i – 1] + A[i] and A[i]
- return max in dp
Let us see the following implementation to get a better understanding −
Example (Python)
class Solution(object): def maxSubArray(self, nums): """ :type nums: List[int] :rtype: int """ dp = [0 for i in range(len(nums))] dp[0] = nums[0] for i in range(1,len(nums)): dp[i] = max(dp[i-1]+nums[i],nums[i]) #print(dp) return max(dp) nums = [-2,1,-3,7,-2,2,1,-5,4] ob1 = Solution() print(ob1.maxSubArray(nums))
Input
nums = [-2,1,-3,7,-2,2,1,-5,4]
Output
8
Updated on: 28-Apr-2020
3K+ Views
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