# Python program to find Largest, Smallest, Second Largest, and Second Smallest in a List?

Array is given,we have to find out maximum, minimum,secondlargest, second smallest number.

## Algorithm

Step 1: input list element
Step 2: we take a number and compare it with all other number present in the list.
Step 3: get maximum, minimum, secondlargest, second smallest number.

## Example code

# To find largest, smallest, second largest and second smallest in a List
def maxmin(A):
maxi = A[0]
secondsmax = A[0]
mini = A[0]
secondmini = A[0]
for item in A:
if item > maxi:
maxi = item
elif secondsmax!=maxi and secondsmax < item:
secondsmax = item
elif item < mini:
mini = item
elif secondmini != mini and secondmini > item:
secondmini = item
print("Largest element is ::>", maxi)
print("Second Largest element is ::>", secondsmax)
print("Smallest element is ::>", mini)
print("Second Smallest element is ::>", secondmini)
# Driver Code
A=list()
n=int(input("Enter the size of the List ::"))
print("Enter the number ::")
for i in range(int(n)):
k=int(input(""))
A.append(int(k))
maxmin(A)

## Output

Enter the size of the List ::6
Enter the number ::
12
30
2
34
90
67
Largest element is ::> 90
Second Largest element is ::> 67
Smallest element is ::> 2
Second Smallest element is ::> 12

Updated on: 23-Jun-2020

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