Java program to find Largest, Smallest, Second Largest, Second Smallest in an array

Java Object Oriented Programming Programming

To find largest, smallest, second largest, second smallest in an array, the code is as follows -

Example

import java.util.*;
public class Demo {
   public static void main(String []args){
      int arr[] = {55, 10, 8, 90, 43, 87, 95, 25, 50, 12};
      System.out.println("Array = "+Arrays.toString(arr));
      Arrays.sort(arr);
      System.out.println("Sorted Array = "+Arrays.toString(arr));
      System.out.println("Smallest element = "+arr[0]);
      System.out.println("2nd Smallest element = "+arr[0]);
      System.out.println("Largest element = "+arr[9]);
      System.out.println("2nd Largest element = "+arr[8]);
   }
}

Output

Array = [55, 10, 8, 90, 43, 87, 95, 25, 50, 12]
Sorted Array = [8, 10, 12, 25, 43, 50, 55, 87, 90, 95]
Smallest element = 8
2nd Smallest element = 8
Largest element = 95
2nd Largest element = 90

Example

Let us now see another example:

Live Demo

import java.util.*;
public class Demo {
   public static void main(String []args){
      int a;
      int arr[] = {55, 10, 8, 90, 43, 87, 95, 25, 50, 12};
      System.out.println("Array = "+Arrays.toString(arr));
      int count = arr.length;
      for (int i = 0; i < count; i++) {
         for (int j = i + 1; j < count; j++) {
            if (arr[i] > arr[j]) {
               a = arr[i];
               arr[i] = arr[j];
               arr[j] = a;
            }
         }
      }
      System.out.println("Smallest: "+arr[0]);
      System.out.println("Largest: "+arr[count-1]);
      System.out.println("Second Smallest: "+arr[1]);
      System.out.println("Second Largest: "+arr[count-2]);
   }
}

Output

Array = [55, 10, 8, 90, 43, 87, 95, 25, 50, 12]
Smallest: 8
Largest: 95
Second Smallest: 10
Second Largest: 90

AmitDiwan

Published on 02-Jan-2020 10:40:20

Previous Page Print Page