Python Program to Accept Three Digits and Print all Possible Combinations from the Digits

When generating all possible combinations of three digits, we can use nested loops to create permutations where each digit appears exactly once in different positions. This approach uses three nested loops with conditional checks.

Example

first_num = int(input("Enter the first number..."))
second_num = int(input("Enter the second number..."))
third_num = int(input("Enter the third number..."))

digits = []
print("The first number is")
print(first_num)
print("The second number is")
print(second_num)
print("The third number is")
print(third_num)

digits.append(first_num)
digits.append(second_num)
digits.append(third_num)

print("All possible combinations:")
for i in range(0, 3):
    for j in range(0, 3):
        for k in range(0, 3):
            if(i != j and j != k and k != i):
                print(digits[i], digits[j], digits[k])

Output

Enter the first number...3
Enter the second number...5
Enter the third number...8
The first number is
3
The second number is
5
The third number is
8
All possible combinations:
3 5 8
3 8 5
5 3 8
5 8 3
8 3 5
8 5 3

How It Works

The algorithm uses three nested loops to generate all possible arrangements:

• The three digits are taken as input from the user

• An empty list called digits is created to store the numbers

• The input numbers are displayed and appended to the list

• Three nested loops iterate through indices 0, 1, and 2

• The condition i != j and j != k and k != i ensures each digit appears only once per combination

• Valid combinations are printed using the list indices

Alternative Using itertools

Python's itertools module provides a built-in function for permutations ?

import itertools

digits = [3, 5, 8]
print("All possible combinations using itertools:")

for combo in itertools.permutations(digits):
    print(combo[0], combo[1], combo[2])

All possible combinations using itertools:
3 5 8
3 8 5
5 3 8
5 8 3
8 3 5
8 5 3

Conclusion

Using nested loops with conditional checks generates all permutations of three digits. The itertools.permutations() function provides a more concise alternative for the same result.