# C++ program to convert all digits from the given range into words

C++Server Side ProgrammingProgramming

Suppose we have two digits a and b. We shall have to convert each digit into words and print them one by one. Printing digits into words means for a digit 5, it should print "Five".

So, if the input is like a = 2, b = 6, then the output will be

Two
Three
Four
Five
Six

To solve this, we will follow these steps −

• if d < 0 and d > 9, then:
• return ("Beyond range of 0 - 9")
• otherwise when d is same as 0, then:
• return ("Zero")
• otherwise when d is same as 1, then:
• return ("One")
• otherwise when d is same as 2, then:
• return ("Two")
• otherwise when d is same as 3, then:
• return ("Three")
• otherwise when d is same as 4, then:
• return ("Four")
• otherwise when d is same as 5, then:
• return ("Five")
• otherwise when d is same as 6, then:
• return ("Six")
• otherwise when d is same as 7, then:
• return ("Seven")
• otherwise when d is same as 8, then:
• return ("Eight")
• otherwise when d is same as 9, then:
• return ("Nine")
• From the main method, do the following:
• for i in range a to be, do
• solve(i)
• move cursor to the next line

## Example

Let us see the following implementation to get better understanding −

#include <iostream>
using namespace std;
void solve(int d){
if(d < 0 || d > 9){
cout << "Beyond range of 0 - 9";
}else if(d == 0){
cout << "Zero";
}else if(d == 1){
cout << "One";
}else if(d == 2){
cout << "Two";
}else if(d == 3){
cout << "Three";
}else if(d == 4){
cout << "Four";
}else if(d == 5){
cout << "Five";
}else if(d == 6){
cout << "Six";
}else if(d == 7){
cout << "Seven";
}else if(d == 8){
cout << "Eight";
}else if(d == 9){
cout << "Nine";
}
}
int main(){
int a = 2, b = 6;
for(int i = a; i <= b; i++){
solve(i);
cout << endl;
}
}


## Input

2, 6

## Output

Two
Three
Four
Five
Six