# Program to remove all nodes of a linked list whose value is same as in Python

PythonServer Side ProgrammingProgramming

Suppose we have a singly linked list, and one target, we have to return the same linked after deleting all nodes whose value is same as target.

So, if the input is like [5,8,2,6,5,2,9,6,2,4], then the output will be [5, 8, 6, 5, 9, 6, 4, ]

To solve this, we will follow these steps −

• head := node
• while node and node.next are not null, do
• while value of next of node is same as target, do
• next of node := next of next of node
• node := next of node
• if value of head is same as target, then
• return next of head
• otherwise,
• return head

Let us see the following implementation to get better understanding −

## Example

class ListNode:
def __init__(self, data, next = None):
self.val = data
self.next = next
def make_list(elements):
head = ListNode(elements)
for element in elements[1:]:
ptr = head
while ptr.next:
ptr = ptr.next
ptr.next = ListNode(element)
return head
def print_list(head):
ptr = head
print('[', end = "")
while ptr:
print(ptr.val, end = ", ")
ptr = ptr.next
print(']')
class Solution:
def solve(self, node, target):
head = node
while (node and node.next):
while node.next.val == target:
node.next = node.next.next
node = node.next
if head.val == target:
return head.next
else:
return head
ob = Solution()
head = make_list([5,8,2,6,5,2,9,6,2,4])
ob.solve(head, 2)
print_list(head)

## Input

[5,8,2,6,5,2,9,6,2,4]

## Output

[5, 8, 6, 5, 9, 6, 4, ]
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