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# Program to find an element in list whose value is same as its frequency in Python

Suppose we have a list of numbers called nums, we have to check whether there is an element whose frequency in the list is same as its value or not.

So, if the input is like [2, 4, 8, 10, 4, 4, 4], then the output will be True

To solve this, we will follow these steps −

- res := a new map to store value wise frequency
- for each key value pair (k,v) in res, do
- if k is same as v, then
- return True

- if k is same as v, then
- return False

Let us see the following implementation to get better understanding −

## Example

class Solution: def solve(self, nums): res = {} for i in nums: try: res[i] += 1 except: res[i] = 1 for k,v in res.items(): if k == v: return True return False ob = Solution() print(ob.solve([2, 4, 8, 10, 4, 4, 4]))

## Input

[2, 4, 8, 10, 4, 4, 4]

## Output

True

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