Program to find greater value between a^n and b^n in C++

In this tutorial, we will be discussing a program to find greater value between a^n and b^n.

For this we will be provided with three numbers. Our task is to calculate a^n and b^n and return back the greater of those values.


 Live Demo

#include <bits/stdc++.h>
using namespace std;
//finding the greater value
void findGreater(int a, int b, int n){
   if (!(n & 1)) {
      a = abs(a);
      b = abs(b);
   if (a == b)
      cout << "a^n is equal to b^n";
   else if (a > b)
      cout << "a^n is greater than b^n";
      cout << "b^n is greater than a^n";
int main(){
   int a = 12, b = 24, n = 5;
   findGreater(a, b, n);
   return 0;


b^n is greater than a^n

Updated on: 09-Sep-2020


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