Program to count maximum number of distinct pairs whose differences are larger than target in Python

Suppose we have a list of numbers called nums and another value target. We have to find the maximum number of pairs where for each pair i < j, i and j are not in any other pair, and |nums[i] - nums[j]| >= target.

So, if the input is like nums = [2, 4, 6, 10, 11], target = 5, then the output will be 2, as we can get pairs: (2, 6), (5, 10)

To solve this, we will follow these steps −

• N := size of A
• sort the list A
• ans := 0
• j := N / 2
• for i in range 0 to N / 2, do
  • while j < N and A[j] - A[i] < target, do
    • j := j + 1
  • if j < N, then
    • ans := ans + 1
    • j := j + 1
• return ans

Let us see the following implementation to get better understanding −

Example

 Live Demo

class Solution:
   def solve(self, A, target):
      N = len(A)
      A.sort()
      ans = 0
      j = N >> 1
      for i in range(N >> 1):
         while j < N and A[j] - A[i] < target:
            j += 1
         if j < N:
            ans += 1
            j += 1
      return ans
ob = Solution()
nums = [2, 4, 6, 10, 11]
target = 5
print(ob.solve(nums, target))

Input

[2, 4, 6, 10, 11], 5

Output

2

Arnab Chakraborty

Updated on: 20-Oct-2020

188 Views

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