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Suppose there is a function f(x), that counts number of (p, q) pairs, such that

- 1 < p <= q <= x
- p and q are coprime
- p * q = x So if we have n.

We have to find sum f(x[i]) for all i in range 1 to n.

So, if the input is like 12, then the output will be 3, because x values are ranging from 1 to 12.

- When x = 6, the valid pair is (2, 3) so f(6) = 1
- When x = 10, the valid pair is (2, 5) so f(10) = 1
- When x = 12, the valid pair is (3, 4) so f(12) = 1

so there are total 3 pairs.

To solve this, we will follow these steps −

- count := 0
- sqr := integer part of (square root of n) + 1
- for base in range 2 to sqr - 1, do
- for i in range 1 to minimum of base and floor of (n / base - base + 1), do
- if gcd of base and i) is not same as 1, then
- go for next iteration

- count := count + floor of (n - i * base)/(base * base)

- if gcd of base and i) is not same as 1, then

- for i in range 1 to minimum of base and floor of (n / base - base + 1), do
- return count

Let us see the following implementation to get better understanding −

from math import sqrt, gcd def solve(n): count = 0 sqr = int(sqrt(n)) + 1 for base in range(2, sqr): for i in range(1, min(base, n // base - base + 1)): if gcd(base, i) != 1: continue count += (n - i * base) // (base * base) return count n = 12 print(solve(n))

12

3

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