# Program to convert roman numeral to integer in Python?

Suppose we have a roman numeral; we have to convert it into number. As we know a Roman numeral is represented by symbols from left to right from greatest to least, the only exception being when representing one less than a symbol. Some roman numeral symbol meanings are as follows:

• 'M': 1000

• 'D': 500

• 'C': 100

• 'L': 50

• 'X': 10

• 'V': 5

• 'I': 1

So, if the input is like numeral = "MCLXVI", then the output will be 1166, as M = 1000, C = 100, total is 1100, then L = 50, X = 10, VI = 6 so total is 1166.

To solve this, we will follow these steps:

take numeral list as mentioned above

• ans := 0

• n := size of numeral

• for each index idx and value c numeral, do

• if idx < n - 1 and d[c] < d[numeral[idx + 1]], then

• ans := ans - d[c]

• otherwise,

• ans := ans + d[c]

• return ans

Let us see the following implementation to get better understanding:

## Example

Live Demo

class Solution:
def solve(self, numeral):
d = {"M": 1000, "D": 500, "C": 100, "L": 50, "X": 10, "V": 5, "I": 1}
ans = 0
n = len(numeral)
for (idx, c) in enumerate(numeral):
if idx < n - 1 and d[c] < d[numeral[idx + 1]]:
ans -= d[c]
else:
ans += d[c]
return ans

ob = Solution()
numeral = "MCLXVI"
print(ob.solve(numeral))

## Input

"MCLXVI"

## Output

1166