Integer to Base 3 Number in Python

Suppose we have a number n, we have to find the base 3 equivalent of this number as string.

So, if the input is like 17, then the output will be 122.

To solve this, we will follow these steps −

• if n<0:
  • sign := -1
• otherwise sign := blank string
• n := |n|
• if n <3, then
  • return n as string
• s := blank string
• while n is not same as 0, do
  • s := string of (n mod 3) concatenate s
  • n := quotient of (n / 3)
• return sign concatenate s

Let us see the following implementation to get better understanding −

Example

 Live Demo

class Solution:
   def solve(self, n):
      sign = '-' if n<0 else ''
      n = abs(n)
      if n < 3:
         return str(n)
         s = ''
      while n != 0:
         s = str(n%3) + s
         n = n//3
      return sign+s
ob = Solution()
print(ob.solve(17))

Input

17

Output

122