Print matrix in snake pattern in C Programming.

Given an array of nxn size, the program must print the elements of an array in a snake pattern without doing any changes to their original locations

Example

Input: arr[]= 100 99 98 97
   93 94 95 96
   92 91 90 89
   85 86 87 88
Output: 100 99 98 97 96 95 94 93 92 91 90 89 88 87 86 85

The program will traverse each row of a matrix and check for even or odd rows.

If the row is even it will print the elements of that row from left to right
If the row is odd it will print the elements of that row from right to left

Algorithm

START
Step 1 -> create header files for declaring rows and column let’s say of size 4x4
Step 2 -> declare initial variables i and j and array[][] with elements
Step 3 -> Loop For i=0 and i<M and i++
   IF i%2==0
      Loop For j=0 and j<N and j++
         Print arr[i][j]
      End
   End
   Else
      Loop For j=N-1 and j>=0 and j—
         Print arr[i][j]
      End
   End
STOP

Example

Live Demo

#include<stdio.h>
#define M 4
#define N 4
int main() {
   int i,j;
   int arr[M][N] = {
      { 100, 99, 98, 97 },
      { 93, 94, 95, 96 },
      { 92, 91, 90, 89 },
      { 85, 86, 87, 88 }
   };
   for (i = 0; i < M; i++) { //for rows
      if (i % 2 == 0) {
         for (j = 0; j < N; j++) // for column
            printf("%d ",arr[i][j]);
      } else{
         for (j = N - 1; j >= 0; j--)
            printf("%d ",arr[i][j]);
      }
   }
   return 0;
}

Output

if we run the above program then it will generate the following output

100 99 98 97 96 95 94 93 92 91 90 89 88 87 86 85

Sunidhi Bansal

Published on 04-Sep-2019 06:08:53

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