Print matrix in snake pattern from the last column in C Programming.

CServer Side ProgrammingProgramming

Given an array of nxn size, the program must print the elements of an array in a snake pattern starting from the last column that means from arr[0][n]th element without doing any changes to their original locations.

Example

Input: arr[]= 100 99 98 97
   93 94 95 96
   92 91 90 89
   85 86 87 88
Output: 97 98 99 100 96 95 94 93 92 91 90 89 88 87 86 85

Algorithm

START
Step 1 -> declare initial variable as int n to 5, i and j
Step 2 -> declare array of 2-D matrix with elements
Step 3 -> Loop For i=0 and i<n and i++
   IF i%2==1
      Loop For j=0 and j<n and j++
         Print arr[i][j]
      End
   End
   Else
      Loop For j=n-1 and j>=0 and j--
         Print arr[i][j]
      End
   End
STOP

Example

 Live Demo

#include <stdio.h>
int main(){
   int n = 5;
   int arr[][5]= {
      {10, 20, 30, 40, 50},
      { 60, 70, 80, 90, 100 },
      { 110, 120, 130, 140, 150 },
      { 160, 170, 180, 190, 200 },
      { 210, 220, 230, 240, 250 }
   };
   for (int i = 0; i < n; i++) { //from column as we must start from the end
      if (i%2 == 1)
         for (int j = 0; j < n; j++)
            printf("%d ", arr[i][j]);
      else
         for (int j = n - 1; j >= 0; j--)
            printf("%d ", arr[i][j]);
      }
   return 0;
}

Output

if we run the above program then it will generate the following output

50 40 30 20 10 60 70 80 90 100 150 140 130 120 110 160 170 180 190 200 250 240 230 220 210
raja
Published on 04-Sep-2019 06:13:45
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